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2 years ago

Which expression is equivalent to -8 - 15 ?

Mathematics

1 answer:

aksik [14]2 years ago

6 0

no mind the extra words it would let me send it but i should be -24

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In a marathon 90% runner were managed to complete it and 30% were men if 270 men completed it how many total runner began the ma

Maurinko [17]

Answer:

1000 runners

Step-by-step explanation:

Take total number of runners to be -----------x

90% of x managed to complete the marathon= 90/100 × x =0.9x

30% of those who completed the marathon were men= 30% × 0.9x

=0.3×0.9x= 0.27x

=270 men completed the marathon; this means

0.27x=270--------------------------------find x by dividing both sides by 0.27

x= 270/0.27

x=1000 runners

7 0

3 years ago

Read 2 more answers

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=

Leno4ka [110]

1 step: $S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}$ , $S_{3}=T_{1}+T_{2}+T_{3}$ , then
$S_{5}-S_{3}=T_{4}+T_{5}=5$ .

2 step: $T_{n}=T_{1}*q^{n-1}$ , then
$T_{6}=T_{1}*q^{5}$
$T_{5}=T_{1}*q^{4}$
$T_{4}=T_{1}*q^{3}$
$T_{3}=T_{1}*q^{2}$
and $\left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right.$ will have form $\left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right.$ and dividing first equation on second we obtain $\frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}$ . So, $\frac{(q-1)(q+1)}{q+1} = \frac{1}{2}$ and $q-1= \frac{1}{2}$ , $q= \frac{3}{2}$ - the common ratio.

4 step: Insert $q= \frac{3}{2}$ into equation $T_{1}*q^{3}*(q+1)=5$ and obtain $T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5$ , from where $T_{1}= \frac{16}{27}$ .

5 0

2 years ago

If you invest $1,000 in an account paying 4% interest compounded quarterly,lhow much money will you have after 3 years? A.)$1,50

polet [3.4K]

Answer:

C is closest to the actual result, $1126.03.

Step-by-step explanation:

Use the Compound Amount formula: A = P(1 + r/n)^(nt), where:

P is the original principal; r is the interest rate as a decimal fraction; n is the number of compounding periods per year, and t is the number of years.

Then we have A = $1000(1 + 0.04/4)^(4*3), or

= $1000(1.01)^12 = $1126.03

7 0

2 years ago

Find the side and measure B

valentinak56 [21]

When angle opposite to the unknown sides and other two sides are given then we use law of cosines

Law of cosine

$c^2 = a^2 + b^2 - 2ab cos(c)$