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3 years ago

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Which expression is not equivalent to 75(12+16)

1 answer:

Fed [463]3 years ago

5 0

12ksidhdowjbwi12538637374744874

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Solve using the standard algorithm 232 * 4 =

miskamm [114]

It's = to 928 you just have to multiply 232 * 4
what is (),., * and x are multiplication sings
HOPE THIS HELPS

6 0

3 years ago

Suppose a, b denotes of the quadratic polynomial x² + 20x - 2022 & c, d are roots of x² - 20x + 2022 then the value of ac(a

Alja [10]

<h3><u>Correct Question :- </u></h3>

$\sf\:a,b \: are \: the \: roots \: of \: {x}^{2} + 20x - 2020 = 0 \: and \: \\ \sf \: c,d \: are \: the \: roots \: of \: {x}^{2} - 20x + 2020 = 0 \: then \:$

$\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) =$

(a) 0

(b) 8000

(c) 8080

(d) 16000

$\large\underline{\sf{Solution-}}$

Given that

$\red{\rm :\longmapsto\:a,b \: are \: the \: roots \: of \: {x}^{2} + 20x - 2020 = 0}$

We know

$\boxed{\red{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}$

$\rm \implies\:ab = \dfrac{ - 2020}{1} = - 2020$

And

$\boxed{\red{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}$

$\rm \implies\:a + b = - \dfrac{20}{1} = - 20$

Also, given that

$\red{\rm :\longmapsto\:c,d \: are \: the \: roots \: of \: {x}^{2} - 20x + 2020 = 0}$

$\rm \implies\:c + d = - \dfrac{( - 20)}{1} = 20$

and

$\rm \implies\:cd = \dfrac{2020}{1} = 2020$

Now, Consider

$\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)$

$\sf \: = {ca}^{2} - {ac}^{2} + {da}^{2} - {ad}^{2} + {cb}^{2} - {bc}^{2} + {db}^{2} - {bd}^{2}$

$\sf \: = {a}^{2}(c + d) + {b}^{2}(c + d) - {c}^{2}(a + b) - {d}^{2}(a + b)$

$\sf \: = (c + d)( {a}^{2} + {b}^{2}) - (a + b)( {c}^{2} + {d}^{2})$

$\sf \: = 20( {a}^{2} + {b}^{2}) + 20( {c}^{2} + {d}^{2})$

$\sf \: = 20\bigg[ {a}^{2} + {b}^{2} + {c}^{2} + {d}^{2}\bigg]$

We know,

$\boxed{\tt{ { \alpha }^{2} + { \beta }^{2} = {( \alpha + \beta) }^{2} - 2 \alpha \beta \: }}$

So, using this, we get

$\sf \: = 20\bigg[ {(a + b)}^{2} - 2ab + {(c + d)}^{2} - 2cd\bigg]$

$\sf \: = 20\bigg[ {( - 20)}^{2} + 2(2020) + {(20)}^{2} - 2(2020)\bigg]$

$\sf \: = 20\bigg[ 400 + 400\bigg]$

$\sf \: = 20\bigg[ 800\bigg]$

$\sf \: = 16000$

Hence,

$\boxed{\tt{ \sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) = 16000}}$

<em>So, option (d) is correct.</em>

4 0

3 years ago

94 POINTS BC ITS THE HIGHEST!!!!

slavikrds [6]

Answer:

1- 19, 2- 27

Step-by-step explanation:

6.05 - 2.25

= 3.8 divided by 0.20

=19

7.65 - 2.25

= 5.4 divided by 0.20

= 27

4 0

4 years ago

Read 2 more answers

Help please I just don't know

Veronika [31]

What do you need help with

8 0

3 years ago

Read 2 more answers

Simplify: (4 /5 + 6/ 25 ) X (8/ 9 + −8 /7 )

Westkost [7]

Answer: -416/1575

Step-by-step explanation:

$\frac{4}{5}=\frac{20}{25} \implies \frac{4}{5}+\frac{6}{25}=\frac{26}{25}\\$

$\frac{8}{9}=\frac{56}{63}\\\\-\frac{8}{7}=-\frac{72}{63}\\\\\implies \frac{8}{9}-\frac{8}{7}=-\frac{16}{63}$

$\frac{26}{25} \times -\frac{16}{63}=-\frac{416}{1575}$

6 0

2 years ago