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Makovka662 [10]
2 years ago
13

Which decimal is the least 0.84 or 0.092 or 0.184 0.199

Mathematics
1 answer:
Afina-wow [57]2 years ago
4 0
0.092 is the least because it has 0 in the tenths place value.
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X/4 - x/6 = 1<br><br> please help
Archy [21]
To solve this multiply through by the LCM of 4 and 6, which is 12:-

12 * x/4 - 12 * x/6 = 1*12

3x - 2x = 12

x = 12  answer
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3 years ago
In a​ poll, 1,004 adults in a certain country were asked whether they favor or oppose the use of​ "federal tax dollars to fund m
WARRIOR [948]

Answer:

The range of values likely to contain the true value of the population parameter is between 44% and 52%.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

These bounds are dependent of the sample mean and of the margin of error.

The lower bound is the sample mean subtracted by the margin of error, while the upper bound is the margin of error added to the sample mean.

The confidence interval is likely to contain the true value of the population parameter.

In this question:

Sample mean: 48%

Margin of error: 4%

48 - 4 = 44%

48 + 4 = 52%

The range of values likely to contain the true value of the population parameter is between 44% and 52%.

7 0
2 years ago
Old Grandpa Joe left half his money to his granddaughter and half that amount to his grandson.
Usimov [2.4K]

Answer:

£12000

Step-by-step explanation:

Granddaughter -- 1/2 of x

Grandson -- 1/2(1/2 of x)

Brother -- 1/6 of x

Dogs' home -- £1000

Therefore,

\frac{x}{2} + \frac{x}{4} + \frac{x}{6} + 1000 = x

x = 12000

Thenks and mark me brainliest :)

7 0
3 years ago
Write in exponent form 85
Nataly [62]

We are given 85

Firstly, we will find all possible factors of 85

we can write it as

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LekaFEV [45]
<h2><u>Given</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{x =  - 8}}}

<h2><u>Solution</u><u>:</u><u>-</u></h2>

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  = 3 \times  - 8 + 34}}}

{ \large{➢ \:  \:  \bf{ \dfrac{2y}{3}  =  - 24 + 34}}}

{ \large{ \bf{ ➢ \:  \: \cancel{2}y = 3 \times { \cancel{(10)} {} \:  \:  ^{5} }}}}

{ \large{ \therefore{  \bf{y = 15 \:  \: Ans.}}}}

3 0
3 years ago
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