V1=(-2,4)=(x1,y1)→x1=-2, y1=4
V2=(4,0)=(x2,y2)→x2=4, y2=0
V3=(2,-3)=(x3,y3)→x3=2, y3=-3
V4=(x4,y4)→x4=?, y4=?
V1-V2
dx=x2-x1=4-(-2)=4+2→dx=6
dy=y2-y1=0-4→dy=-4
V4-V3
dx=x3-x4→6=2-x4
Solving for x4:
6=2-x4→6-2=2-x4-2→4=-x4→(-1)(4=-x4)→-4=x4→x4=-4
dy=y3-y4→-4=-3-y4
Solving for y4:
-4=-3-y4→-4+3=-3-y4+3→-1=-y4→(-1)(-1=-y4)→1=y4→y4=1
V4=(x4, y4)→V4=(-4, 1)
Answer: The coordinates of the fourth vertex are (-4,1)
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Answer:
The x-intercepts will be, x= 7 or x =9
Step-by-step explanation:
f(x)= x^2 -16x+63
At the x-intercept, f(x) is zero.
Therefore;
x² - 16x + 63 = 0
solving it quadratically;
product = 63
Sum = -16
x² - 9x - 7x + 63 = 0
x(x-9) - 7( x-9) = 0
(x-7) (x-9) = 0
x = 7 or x = 9
Therefore;
The x-intercepts will be, x= 7 or x =9
Answer:2405.0
Step-by-step explanation:
Answer:
3/8 tan²A
Step-by-step explanation:
sinB = √3/2 sinA and cos B= √2 cosA (from given)