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Lynna [10]
3 years ago
10

What is the answer to f(x)=-3x^2-20

Mathematics
2 answers:
nexus9112 [7]3 years ago
6 0
X = -6 hope this helps
Veronika [31]3 years ago
3 0

\huge \boxed{\mathfrak{Question} \downarrow}

  • What is the answer to \sf \: f ( x ) = - 3 x ^ { 2 } - 20

\huge \boxed{\mathfrak{Answer} \downarrow}

\large \boxed{ \bf \: - 6x}

\huge \boxed{\mathfrak{Explanation} \downarrow}

\large \sf \: f ( x ) = - 3 x ^ { 2 } - 20

  • The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of \sf \: ax^{n} is \sf \: nax^{n-1}.

\large \sf \: 2\times ( -3x)^{2-1}

  • Multiply 2 times - 3.

\large \sf \: - 6x^{2-1}

  • Subtract 1 from 2.

\large \sf \: - 6x^{1}

  • For any term t, t¹ = t.

\large \boxed{ \bf \: - 6x}

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If f(x) = -2x^2 + 3 then f(-5) = ??
Sladkaya [172]

F(-5)= -2x^2+3

-5*-5=25

25*-2=-50

F=-50+3

F=-47

5 0
3 years ago
Which angles are adjacent angles to 3? Select all that apply
sattari [20]

Two Answers: Angle 1, Angle 4

Adjacent angles share a common segment, line, or ray. Think of two adjacent rooms sharing a common wall.

3 0
3 years ago
Find the 8th term of the geometric sequence whose common ratio is 3/2 and whose first term is 3
saul85 [17]

Answer:

51.2578125

Step-by-step explanation:

3 * (3/2)^(8 - 1)

3 *(3/2)^7

51.2578125

6 0
3 years ago
Need help to answer
Korolek [52]
Remember, you can do anything to an equation as long as you do it to both sides

times 4 both sides because we hate fractions
3x+8=16x-4
minus 3x both sides
8=13x-4
add 4 both sides
12=13x
divide both sides by 13
12/13=x
x=12/13
4 0
3 years ago
The mass, m grams, of a radioactive substance, present at time t days after first being observed, is given by the formula m=24e^
Reika [66]

Answer:

(i) The value of<em> m</em> when t = 30 is 13.2

(ii) The value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) The rate of the mass when t=50 is -0.18            

Step-by-step explanation:

(i) The <em>m</em> value when t = 30 is:

m = 24e^{-0.02t} = 24e^{-0.02*30} = 13.2

Then, the value of<em> m</em> when t = 30 is 13.2

(ii) The value of the mass when t=0 is:

m_{0} = 24e^{-0.02t} = 24e^{-0.02*0} = 24    

Now, the value of <em>t </em>is:

ln(\frac{m_{0}/2}{24}) = -0.02t

t = -\frac{ln(\frac{24}{2*24})}{0.02} = 34.7

Hence, the value of <em>t</em> when the mass is half of its value at t=0 is 34.7

(iii) Finally, the rate at which the mass is decreasing when t=50 is:

\frac{dm}{dt} = \frac{d}{dt}(24e^{-0.02t}) = 24(e^{-0.02t})*(-0.02) = -0.48*                            (e^{-0.02*50}) = -0.18

Therefore, the rate of the mass when t=50 is -0.18.

I hope it helps you!                  

3 0
3 years ago
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