Answer:
13.92
Step-by-step explanation:
We have that the critical z-score associated with 85% to the left is 1.04, we know that by table.
So we have to:
m + z * (sd) = 16
where m is the mean, z is the critical z-scor and sd is the standard deviation, if we replace we are left with:
m + 1.04 * (2) = 16
m = 16 - 1.04 * (2)
m = 13.92
Therefore, the average weight if 85% of cucumbers weigh less than 16 ounces is 13.92
In point slope form, the equation is y-7=(-10/3)(x+9). In slope-intercept form, it is y=(-10/3)x-23.
First find the slope of the line. The formula for slope is
m=(y₂-y₁)/(x₂-x₁)
Using our points, we have
m=(-3-7)/(-6--9) = -10/3
Plug this into point slope form:
y-y₁=m(x-x₁)
y-7=(-10/3)(x--9)
y-7=(-10/3)(x+9)
Using the distributive property:
y-7=(-10/3)*x+(-10/3)*9
y-7=(-10/3)x-90/3
y-7=(-10/3)x-30
Add 7 to both sides:
y=(-10/3)x-23
W = L - 15
WL = 76
(L-15)L = 76
L^2 - 15L - 76 = 0
(L-19)(L+4) = 0
L = 19 or -4
Since a length cannot be negative, the length must be 19 units.
The width is 19-15=4 units.
Answer:
y=4x+13
Step-by-step explanation:
Ig, hope it helps
