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castortr0y [4]
2 years ago
7

Write each mixed number as an improper fraction :2 3/7​

Mathematics
2 answers:
tekilochka [14]2 years ago
7 0

Answer:

Step-by-step explanation:

amm18122 years ago
3 0

Answer:

17/7

Step-by-step explanation:

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I need help please <br>...... no linksssssssssss​
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Step-by-step explanation:

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2 years ago
What is the answer to x
Ierofanga [76]
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8 0
3 years ago
Read 2 more answers
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
What is the gfc of 16 and 8​
lesantik [10]

Answer:

<h2>Greatest common factor of 16 and 8 is 8 .....</h2>
6 0
3 years ago
Round the answer to the nearest
kykrilka [37]

By knowing the <em>blood</em> pressure and applying the <em>quadratic</em> formula, the age of a man whose normal <em>blood</em> pressure is 129 mm Hg is 40 years old.

<h3>How to use quadratic equations to determine the age of a man in terms of blood pressure</h3>

In this problem we have a <em>quadratic</em> function that models the <em>blood</em> pressure as a function of age. As the latter is known, we must use the quadratic formula to determine the former:

129 = 0.006 · A² - 0.02 ·A + 120

0.006 · A² - 0.02 · A - 9 = 0

A = \frac{0.02 \pm \sqrt{0.006^{2}-4\cdot (0.006)\cdot (- 9)}}{2\cdot (0.006)}

A = 1.667 + 38.733

A = 40

By knowing the <em>blood</em> pressure and applying the <em>quadratic</em> formula, the age of a man whose normal <em>blood</em> pressure is 129 mm Hg is 40 years old.

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

4 0
1 year ago
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