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lord [1]
3 years ago
8

Choose the linear inequality that describes each graph.

Mathematics
2 answers:
oee [108]3 years ago
8 0

Answer:

y > -5x + 3

Step-by-step explanation:

Starting from the y-intercept of [0, 3],you do \frac{rise}{run}by either moving five blocks <em>north</em><em> </em>over one block <em>west</em><em> </em>or five blocks <em>south</em><em> </em>over one block <em>east</em><em> </em>[<em>west</em> and <em>south</em> are negatives], then you shade everything to the right of the line because using the zero-interval test, also known as the test point [origin], we can determine what side of a line to shade. This is done by plugging "0" in for both <em>y</em><em> </em>and <em>x</em><em>,</em><em> </em>then determining whether false or true will tell you which side to shade. In this case, we shade to the right of the line because when we plug the test point into the function, we get this false statement:

0 ≯ 3

So, we do not want to shade the side with the origin. We would want to shade the OPPOSITE side, which is what you see in the graph.

I am joyous to assist you anytime.

* In this case, do not worry about whether to use dashed or solid lines because since your inequality symbol is a <em>greater</em><em> </em><em>than</em><em> </em>symbol, that already tells you that you need a dashed line, otherwise it would be solid if it were a <em>greater</em><em> </em><em>than</em><em> </em><em>or</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em>symbol [≥].

** Picking ANY point in the shaded region of a linear inequality equation will ALWAYS make an authentic statement.

Crazy boy [7]3 years ago
7 0

Answer:

The answer is A. y > – 5x + 3.

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Linda goes water-skiing one sunny afternoon. After skiing for 15 min, she signals to the driver of the boat to take her back to
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60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2


abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
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y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.


d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
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Answer:

Step-by-step explanation:

w=204.8

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