Referring to the figure, is the transformation a

Mathematics

1 answer:

valkas [14]2 years ago

5 0

Answer:

yes.

Step-by-step explanation:

90 Degree Rotation. When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x).

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8 less than 2 times a number is greater than the sum of the same number and 9

lyudmila [28]

step-by-step explanation:

every time we see "a number" or "the same number," we can add a variable (we'll use x here). rewriting the problem, we get: 8 less than 2 times x is gr8er than the sum of x and 9.

next, we can work backwards to write an inequality. we know from the word problem above that the number on the left side of the equation is 8 less than 2x, so we can rewrite that part like this: 2x-8.

for the right side of the equation, all we have to do is simplify "the sum of x and 9" to x + 9. so now the inequality should look like this: 2x - 8 > x + 9.

now we'll solve the inequality just like an equation: subtract x from both sides of the inequality, so now we have: x - 8 > 9.

then, we can add 8 to both sides to get the x by itself, and we get the answer: x > 15

hope this helps! <em>:)</em>

4 0

3 years ago

Pioneer company has given an aptitude test to 71 potential job applicants. The test score had an average of 81 and a standard de

Agata [3.3K]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

In point A:

$\to df = n - 1 = 71-1= 70$

In point B:

$\to t = \frac{(x -X)}{s} = \frac{(93-81)}{8} = \frac{12}{8}= 1.5$

In point C:

For df = 70, the top 5% critical t score

tcrit = 1.666914479

Thus,

$\to 1.666914479 = \frac{(x - 81)}{8}\\\\\to 1.666914479 \times 8 = (x - 81)\\\\\to 13.335315832 = (x - 81)\\\\\to 13.335315832 +81 =x \\\\\to x= 94.335315832$

In point D:

For df = 70, the top 5% critical t score

tcrit = -1.666914479

$\to -1.666914479 = \frac{(x - 81)}{8}\\\\\to -1.666914479 \times 8= (x - 81)\\\\\to -13.335315832= (x - 81)\\\\\to -13.335315832+81 = x \\\\\to x = 67.664684168\\\\$

In point E:

The lower cutoff is 0.10 in the center, which would be around 80 %. The critical point therefore is

tcrit = -1.293762898

$\to -1.293762898 = \frac{(x-81)}{8}\\\\\to -1.293762898 \times 8= (x-81) \\\\\to -1.293762898 \times 8= (x-81) \\\\\to -10.350103184=x-81\\\\\to -10.350103184+81=x\\\\\to x=70.649896816$