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scZoUnD [109]
2 years ago
14

HELP PLS will give brainliest- please provide how to do it aswell

Mathematics
2 answers:
balu736 [363]2 years ago
6 0

Answer:

I'm not exactly sure yet but i believe the 3rd choice is best!

Comment!

(Soon i will give reasoning and answer or change it unless i am right)

Tell me stuff in comments i'll see what i can do.

Step-by-step explanation:

Hope i helped!

Thanks,

Your helper :)

Friend me!

seraphim [82]2 years ago
6 0

Answer: D

Step-by-step explanation:

You just have to test pi/6

\dfrac{30}{cos(6*\dfrac{Pi}{6})} =\dfrac{30}{cos(\Pi)} =-30

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2 years ago
One half a number decreased by 3 is 21 what is the equation for this statement
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Question:

What is the equation for the following statement,"One-half of a number decreased by 3 is 21.

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3 years ago
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Step-by-step explanation:

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3 years ago
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Which ordered pair is a solution the the following system?
muminat

Answer:

d is the correct answer .

Step-by-step explanation:

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4 0
3 years ago
Graph and label the image of the figure below after a dilation by a factor of 1/2.
neonofarm [45]
Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\  \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\  \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\  \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0
10 months ago
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