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zmey [24]
3 years ago
8

A linear function has a slope of 2 and passes through the point (0,6). What is the equation of the line?

Mathematics
1 answer:
pychu [463]3 years ago
4 0
A linear function means you’re working with a line. Lines can be stated in slope-intercept form: y=mx+b.

To make it a linear function, you simply replace “y” with “f(x)” notation: f(x) = mx + b

The information you gave told you m=2 and b=6, since (0,b) is the y-intercept.

Putting that all together you have:
f(x) = 2x + 6
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The answer to number 2 is 7
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3 years ago
Help with this math problem
marishachu [46]

see explanations

Step-by-step explanation:

Formula for mid-point is;

midpoint=((x_1+x_2)/2,(y_1+y_2)/2)

1.Given S(-3,4), U(-3,0) and T(5,0) then finding the mid-points

SU = [(-3+-3)/2,(4+0)/2] =(-3,2)

TU= [(-3+5)/2,(0+0)/2] =(1,0)

ST=[(-3+5)/2,(4+0)/2]=(1,2)

2.Mid-point formula for this case given W(-5,1) and Z(3,3) will be;

Midpoint = [ (x₁+x₂)/2,(y₁+y₂)/2]

Midpoint= [(-5+3)/2 ,(1+3)/2]

Midpoint=(1,2)

3. Finding the length of segments and the midpoint of the segments

Formula for length of segment, d, is given as;

For C(-1,5) and D(5,1)

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2} \\\\d=\sqrt{(1-5)^2+(5--1)^2} =\sqrt{-4^2+6^2} =\sqrt{16+36} =\sqrt{52} =7.21

Midpoint of the segment CD will be

[(-1+5)/2,(5+1)/2] = (2,3)

For E (-3,-6) and F(5,0)

d=\sqrt{(0--6)^2+(5--3)^2} =\sqrt{6^2+8^2} =\sqrt{36+64} =\sqrt{100} =10

The midpoint for segment EF will be;

[(-3+5)/2 ,(-6+0)/2] =(1,-3)

For L(-4,4) and M(-1,-5)

d=\sqrt{(-5--4)^2+(-1-4)^2} \\d=\sqrt{-1^2+-5^2} \\\\d=\sqrt{1+25}=\sqrt{26} =5.1

Learn More

Midpoint of a segment :brainly.com/question/10424143

Distance of a segment :brainly.com/question/11591660

Keywords :midpoint, midpoint formula, segment length, line segment

#LearnwithBrainly

4 0
4 years ago
Solve for x: A=2xy what is the answer
USPshnik [31]
The answer is x= A/2y
6 0
4 years ago
Read 2 more answers
I need answer on this graphing va substitution.Problem 7 I tried to solve it but not sure that’s correct
Bond [772]

Given the system of equations:

\begin{gathered} 2x+9y=27 \\ x-3y=-24 \end{gathered}

To solve it by substitution, follow the steps below.

Step 1: Solve one linear equation for x in terms of y.

Let's choose the second equation. To solve it for x, add 3y to each side of the equations.

\begin{gathered} x-3y=-24 \\ x-3y+3y=-24+3y \\ x=-24+3y \end{gathered}

Step 2: Substitute the expression found for x in the first equation.

\begin{gathered} 2x+9y=27 \\ 2\cdot(-24+3y)+9y=27 \\ -48+6y+9y=27 \\ -48+15y=27 \end{gathered}

Step 3: Isolate y in the equation found in step 2.

To do it, first, add 48 to both sides.

\begin{gathered} -48+15y=27 \\ -48+15y+48=27+48 \\ 15y=75 \end{gathered}

Then, divide both sides by 15.

\begin{gathered} \frac{15y}{15}=\frac{75}{15} \\ y=5 \end{gathered}

Step 4: Substitute y by 5 in the relation found in step 1 to find x.

\begin{gathered} x=-24+3y \\ x=-24+3\cdot5 \\ x=-24+15 \\ x=-9 \end{gathered}

Answer:

x = -9

y = 5

or (-9, 5)

Also, you can graph the lines by choosing two points from each equation, according to the picture below.

7 0
1 year ago
Find the slope of the lines joining each of the following pair of points.<br> (3,-2) and (4,7)
madreJ [45]

Answer:

9/7 or 1 2/7

Step-by-step explanation:

use the formula rise/run

7 0
3 years ago
Read 2 more answers
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