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3 years ago

11

Voltage (V), varies directly with resistance (R) in a circuit. If the voltage is 150 volts when the resistance is 480 ohms, find

the voltage when the resistance is 200 ohms.

1 answer:

aliina [53]3 years ago

3 0

62.5 v I think but I’m not sure

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Lubov Fominskaja [6]

Answer:

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Step-by-step explanation:

Add angles together and set to 180°. Solve for x.

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3 years ago

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Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

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3 years ago

How many minutes did Todd use in October

Natalija [7]

Answer:

100 minutes cost Todd $24. He had extra bill of 26.38 - 24 = $2.38

$2.38 = 238 cents

7 cents billed for 1 extra minute

1 cents billed for 1/7 extra minute

238 cents billed for 238/7 = 34 extra minutes

total minutes = 134 minutes

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2 years ago

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borishaifa [10]

Answer:

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Step-by-step explanation:

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3 years ago

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Katarina [22]

Answer:

13

Step-by-step explanation:

-12-(-25)=13

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2 years ago

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