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ANEK [815]
3 years ago
9

Can someone please help me on this

Mathematics
1 answer:
Karolina [17]3 years ago
8 0

it is a because it is the line is in the spot we're it is ststop to go

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Can someone help me I forgot how to do this
Yuliya22 [10]
Perimeter = 7+5+7+5 = 24
8 0
3 years ago
You have a bag which contains 15 slips of paper that are num- bered 1 through 15. You pull a piece of paper from the bag, do not
BARSIC [14]

Answer:

<u>The correct answer is 1/35 (fully simplified fraction)</u>

Step-by-step explanation:

Number of slips of paper in the bag = 15

Number of slips of paper in the bag that are a multiple of 4 = 3 (those numbered 4, 8 and 12)

Using Laplace Rule, that states that the probability of an event X is obtained by dividing the number of results that form event X by the number of possible outcomes, provided that the elementary events are equiprobable, that is, that all possible outcomes have the same probability.

Probability of pulling a 1st piece of paper multiple of 4 = 3/15 = 1/5

Now we have a second event Y that is not independent from the first event X, because now the number of slips is 14 and not 15, you're not returning the first slip of paper.

Probability of pulling a 2nd piece of paper multiple of 4 = Probability of the 1st event * probability of the 2nd event after it happened the 1st one

Probability of pulling a 2nd piece of paper multiple of 4 = 1/5 * 2/14

Probability of pulling a 2nd piece of paper multiple of 4 = 2/70 = 1/35

<u>The probability of pulling two slips of paper both numbered with a multiple of 4 is 1/35.</u>

3 0
3 years ago
Solve by factorising<br><br><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="abs
Paladinen [302]

Step-by-step explanation:

\underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} :

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

\underline{ \underline{ \text{Let's \: solve}}} :

\tt{ {x}^{2}  + 16x +  55 = 0}

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ \tt{ {x}^{2}  + (11 + 5)x + 55 = 0}

⤑ \tt{ {x}^{2}  + 11x + 5x +  55 = 0}

⤑ \tt{x(x + 11) + 5(x + 11) = 0}

⤑ \tt{(x + 5)(x + 11) = 0}

Either :

\tt{x + 5 = 0 \: \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \: Or :  \:  \:  x + 11 = 0}

\sf{⟶ x  = 0 - 5} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:⟶  x =  0 - 11

\tt{⟶x =  - 5 } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:     \:  \:⟶   x =  - 11

\red{ \boxed{ \boxed{ { \tt{Our \: final \: answer :  \boxed{ \underline{  \bold{ \tt{x  =  - 5 \: , - 11}}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0
3 years ago
Please select the best answer from the choices provided ASAP
LuckyWell [14K]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What are the solutions of the system 7x + 3y=-3 and y= -2*?
mafiozo [28]

Answer:

opt 4

Step-by-step explanation:

when x=0, 0+3y= -3, so y=-1    (0,-1) is solution

         when x=3 , 21+3y=-3,  3y= -3-21= -24

                                                    y= -8                  (3,-8) is also solution

8 0
3 years ago
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