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3 years ago

Will make you brainlistt if it is right

Mathematics

1 answer:

dexar [7]3 years ago

3 0

Answer:

The amount of weeks is your independent variable, or X variable, and the height is you dependents variable.

Step-by-step explanation:

I don't know what this question is about so I'm gonna use plants as an example. The amounts of weeks that you are growing a plant is not dependent on anything. Nothing can cause change to that variable, so it would be your X. The height that your plant has grown DOES depend on how long you've grown it, so the amount of weeks, making it your Y variable.

You might be interested in

Solve -1.2x+2.5=0.8x+6.5<br>x=2<br>O<br>x=-4 0

Bond [772]

Answer:

x = - 2

Step-by-step explanation:

Given

- 1.2x + 2.5 = 0.8x + 6.5 ( subtract 0.8x from both sides )

- 2x + 2.5 = 6.5 ( subtract 2.5 from both sides )

- 2x = 4 ( divide both sides by - 2 )

x = - 2

4 0

3 years ago

someone is eating a 50 gram chocolate bar which contains 30% cocoa how many grams of cocoa is in the chocolate bar

DIA [1.3K]

Well , 10% is 5 g so if you times those 5 g by 3 it is 15 g there are 15 grams of cocoa in the chocolate bar

3 0

3 years ago

Read 2 more answers

. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte

Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160$

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240$

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

$\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}$

4 0

2 years ago

Is this a function or a non function?

ElenaW [278]

Answer:

This is a function

Step-by-step explanation:

If you do the Vertical Line Test you can see that the line passes through only one dot at a time. Therefore it is a function. If the line passed through more than one dot at a time then it wouldn't be a function.

4 0

2 years ago

What are the domain and range of the function represented by the set of ordered pairs? \ (-6,5),(-3,2),(-1,0),(5,-4)\

stellarik [79]

Answer:

The domain and the range of the function represented by the set of ordered pairs are {-6, -3, -1, 5} and {5, 2, 0, -4}

Step-by-step explanation:

In any set of ordered pairs,

The domain is the values of x (set of x) ⇒ the first number in each ordered pair

The range is the value of y (set of y) ⇒ the second number in each ordered pair

Let us solve the question

∵ The set of ordered pairs is {(-6, 5), (-3, 2), (-1, 0), (5, -4)}

∵ The first number in each ordered pair represents x

∴ x = -6, -3, -1, 5

∵ The set of x is the domain of the function

∴ The domain of the set of ordered pairs = {-6, -3, -1, 5}

∵ The second number in each ordered pair represents y

∴ y = 5, 2, 0, -4

∵ The set of y is the range of the function

∴ The range of the set of ordered pairs = {5, 2, 0, -4}

The domain and the range of the function represented by the set of ordered pairs are {-6, -3, -1, 5} and {5, 2, 0, -4}

3 0

3 years ago

Read 2 more answers