All categories

2 years ago

HELP PLEASE here’s the picture

Mathematics

1 answer:

bazaltina [42]2 years ago

5 0

Answer:

Hey there,

(It would be good to note that i just learned how to simplify/solve algebraic expretions)

P=21+2w

P/21=2w

then we flip it

2w=p/21 which could also be

w=2(p/21) i think

You might be interested in

Find the nth term:

san4es73 [151]

Answer:

n+3

Step-by-step explanation:

the relationship between those numbers are consistently adding 3 thus n +3

7 0

2 years ago

Read 2 more answers

You and two friends share 7 cookies equally.How many cookies do you each get?

Wewaii [24]

3 and a half cookies! that should be the answer!

7 0

2 years ago

Read 2 more answers

A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable

Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 14, p = 0.3$ .

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066$

$P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014$

$P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002$

$P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024$

$P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002$

$P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0$

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082$

0.0082 = 0.82% probability that he will pass

6 0

2 years ago

There are 12 students in a classroom, including the triplets joey, chloe, and zoe. If 3 of the 12 are randomly selcted to give s

BARSIC [14]

The probability of Joey being first is 1/12. If that happens the probability of Chloe going next is 1/11. Then the probability of zoe being picked next would be 1/10. Then if you multiply all the fractions I gave you you would get 1/1320 which is A. So A. Is your answer!! Hope this helps you out!!

8 0

3 years ago

Read 2 more answers

Order the numbers from least to greatest 10.5, 10.06, 10.64, 10.46

jekas [21]

10.5 10.6 10.46 10.64

6 0

2 years ago

Read 2 more answers