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Igoryamba
3 years ago
5

HELP PLEASE here’s the picture

Mathematics
1 answer:
bazaltina [42]3 years ago
5 0

Answer:

Hey there,

(It would be good to note that i just learned how to simplify/solve algebraic expretions)

P=21+2w

P/21=2w

then we flip it

2w=p/21 which could also be

w=2(p/21) i think

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The possible value of b is:
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Answer please. If you answer, you get 44 points. I don't use the points here. So answer please. I want full work.
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Answer: you simplfy the two equations already there then plug them in to find factors

Step-by-step explanation:

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What is 1/3:2/3 as a unit rate please help
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

let's solve :

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Tim claims that a coin is coming up tails less than half of the time. In 110 tosses, the coin comes up tails 47 times. Using P-v
lilavasa [31]

Answer:

z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531  

p_v =P(z  

If we compare the p value obtained and using the significance level given \alpha=0.1 we have that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.  

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=47 represent the number of tails obtained

\hat p=\frac{47}{110}=0.427 estimated proportion of tails

p_o=0.5 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of tails is lower than 0.5:  

Null hypothesis:p\geq 0.5  

Alternative hypothesis:p < 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.427 -0.5}{\sqrt{\frac{0.5(1-0.5)}{110}}}=-1.531  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and using the significance level given \alpha=0.1 we have that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of tails is significantly less than 0.5.  

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