Answer:
<h3>The answer is option C</h3>
Step-by-step explanation:
6x³ - 4x² - 16x
To factorize the expression first factor out the GCF out
The GCF in the expression is 2x
That's
2x( 3x² - 2x - 8)
Next Factorize the terms in the bracket
To factorize write - 2x as a difference
that's
2x( 3x² + 4x - 6x - 8)
<u>Factor out x from the expression</u>
2x [ x( 3x + 4) - 6x - 8 ]
<u>Next factor out - 2 from the expression</u>
2x [ x ( 3x + 4) - 2( 3x + 4) ]
<u>Factor out 3x + 4 from the expression</u>
We have the final answer as
<h3>2x( 3x + 4)( x - 2)</h3>
Hope this helps you
Answer:
1. B
2. B and C
3.C
4.B the answer is 238 but i guess the rounded
Step-by-step explanation:
Answer:
142×11=1152
Step-by-step explanation:
hope it helps you:)
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
