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svet-max [94.6K]
3 years ago
7

Enter the ZEROS of the function below. Select 2 answers: Let f(x) = x2 − 13x + 30 answers:

Mathematics
2 answers:
____ [38]3 years ago
5 0
We can factor the equation into:
(x-10)*(x-3)
Therefore the roots are:
X = 10
X = 3

allochka39001 [22]3 years ago
3 0

Answer:

Option B and D are correct.

x = 3 and x = 10

Step-by-step explanation:

Given the functions:

f(x) =x^2-13x+30

Split the middle terms:

f(x) =x^2-10x-3x+30

Take out the common factor:

f(x) =x(x-10)-3(x-10)

⇒f(x) =(x-10)(x-3)

To find the zeroes of this function f(x).

Equate f(x) = 0

then;

(x-10)(x-3)=0

By zero product property: if ab=0 then a=0 or b = 0

then;

x-10 = 0 and x-3 = 0

⇒x = 10 and x = 3

Therefore, the zeros of the given function are: x = 10 and 3

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The temperature of coffee served at a restaurant is normally distributed with an average temperature of 160 degrees Fahrenheit a
posledela

Answer:

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 160 degrees

Standard Deviation, σ = 5.4 degrees

We are given that the distribution of temperature of coffee is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.2

P( X < x) = P( z < \displaystyle\frac{x - 160}{5.4})=0.2  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 160}{5.4} = -0.842\\\\x = 155.4532  

Thus,

P_{20}=155.4532

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.

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