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3 years ago

Is this relationship a function? Please help me, this assignment is overdue. ASAP! TYSM!

Mathematics

1 answer:

DENIUS [597]3 years ago

4 0

The answer is taking away 3 so

x-3=y

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Simplify and solve each equation for the x

SpyIntel [72]

Answer:

x = 2

Step-by-step explanation:

2(2x+1-x)=6

2(x+1)=6 add common factors

2x+2=6 distribute the 2

2x=4 subrtract 2 on both sides

x=2 divide 2 on both sides

8 0

3 years ago

HELP WILL GIVE BRAINLIEST

SVEN [57.7K]

Answer:

5/8 = 20/32

Step-by-step explanation:

if you multiply the denominator and the numerator of 5/8 by 4 it will equal 20/32

4 0

3 years ago

Read 2 more answers

Could yall please help me out w this

DENIUS [597]

Answer:

answer is ........ C

Step-by-step explanation:

7 0

3 years ago

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

8 0

3 years ago

Approximately 54% of mathematics students do their homework on time. In a class of 250 students, what is the mean, variance, and

sleet_krkn [62]

Answer:

A) Mean = 135 Variance = 62 Standard Deviation = 8

Step-by-step explanation:

Given that :

Proportion (p) = 54%

Sample size (n) = 250

Using Normal approximation :

Mean = np

Mean = 250 * 0.54 = 135

Variance = npq ; q = 1 - p = 1 - 0.54 = 0.46

Variance = (250 * 0.54 * 0.46) = 62.1 = 62

Standard deviation = √variance = √62.1

Standard deviation = 7.8803553 = 8

6 0

3 years ago