You can find the number of x intercepts by setting f(x) equal to zero giving you 0=x^4-5x^2. You can factor out an x^2 and divide on both sides (when you divide 0 by anything it is still zero so the x^2 disappears), and you are left with 0=x^2-5, which you can solve easily giving you x=+/- sqrt(5). However, the original equation also has an x intercept at (0,0) which you can see by plugging 0 in for x. So the grand total of x intercepts is 3!
Answer:
tanA=34⟹sinA=332+42−−−−−−√=35
Now, we have
sinAcosA=tanA
⟹3/5cosA=tanA
⟹cosA=13×54×3
⟹cosA=45
⟹cosAsinA=4×35×5=1225
Step-by-step explanation:
Answer:
The maximum number of packages that can be made with each package have same number of each item is = 6
Step-by-step explanation:
Given:
Mr. Harris has 48 pencils and 30 notebooks.
To find the number of packages he can make with each package have same number of each item.
Solution:
Number of pencils = 48
Number of notebooks = 30
In order to find the number of packages he can make with each package have same number of each item, we will find the greatest common factor of the given numbers.
<em>To find the G.C.F., we will list down the prime factors of each.</em>
We find that the G.C.F. = 
= 6
Thus, the maximum number of packages that can be made with each package have same number of each item is = 6
3/4 + 4/5 =
15/20 + 16/20 = 31/20
= 1 and 11/20
Answer: 30 people
In the first vineyard, it needs 25 people working for 9 days to finish 30 acres of vineyard. Using this information you can determine the worker speed. The number of worker and days were given will increase the speed, but the area of the vineyard will decrease it. The calculation would be:
Worker speed= worker number * times given / vineyard area
Worker speed= 25 people * 9 days / 30 acres = 7.5 people days /acres
Applying the same calculation into the second vineyard would be:
Worker speed= worker number * times given / vineyard area
7.5 people days /acres = worker number * 5 days / 20 acres
Worker number= (7.5 people days /acres ) / 5 days x 20 acres= 30 people
