Answer: 
Step-by-step explanation:
First integrate f'(x) so we can find the funtion f(x):
![4\int\limits {x} \, dx =4[\frac{1}{2} x^2]=2x^2+C=f(x)](https://tex.z-dn.net/?f=4%5Cint%5Climits%20%7Bx%7D%20%5C%2C%20dx%20%3D4%5B%5Cfrac%7B1%7D%7B2%7D%20x%5E2%5D%3D2x%5E2%2BC%3Df%28x%29)
The initial conditions say that when x = 0, the function equals 5. Let's write that down:
Therefore, the integration constant 'C' must equal 5. This means that our function is:
<span>Left & Right affect the h,
Up & Down affect the k,
Shrink & Stretch affect the "a" (which is in front of the absolute value expression).
1. shift 1 unit to the right and up 2 units → y = |x-1| + 2
2. </span><span>shift 3 units to the left and 7 units down → y = |x + 7| - 7
3. </span><span>vertical shrink by a factor of 1/3 → y =
|x|
4. </span><span>vertical stretch by a factor of 3
→ y = </span><span>3 |x|</span>
3-(-2)
= 3-(-2)
= 3 + 2
= 5
The Answer is 5
Answer:
x = -1 or x = -3
Step-by-step explanation:
x + 3/x = -4
x² + 3 = -4x
x² + 4x + 3 = 0
(x + 1) (x + 3) = 0
x = -1 or x = -3
check: (-1) + (3/-1) = -1 - 3 = -4
(-3) + (3/(-3)) = -3 -1 = 14
