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goblinko [34]
3 years ago
8

A) If a = x and b = 2x2, then 2ab = ​

Mathematics
1 answer:
DiKsa [7]3 years ago
8 0

Answer:

Step-by-step explanation:

a = x

b = 2x^2

ab = x * 2x^2

ab = 2 x^3

2ab = 4 * x^3

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The angle of the roof on kaya’s dollhouse is 56 degrees. she built a scale model of the dollhouse with a scale ratio of 1:4. wha
Alona [7]
The answer I got was letter B; 34
6 0
4 years ago
HELP ASAP will give brainliest
Natalka [10]

Average rate of change is 0

Interpretation: The crop yield did not change from year 5 to year 15

<em><u>Solution:</u></em>

The function that models the yield is:

f(x) = -x^2 + 20x + 75

The average rate of change of f(x) from x = a to x = b is given by the formula:

\text{ average rate of change }=\frac{f(b)-f(a)}{b-a}

Find and interpret the average rate of change from year 5 to year 15

f(5) = -(5)^2 + 20(5) + 75\\\\f(5) = -25 + 100 + 75\\\\f(5) = 150

f(15) = - (15)^2 + 20(15) + 75\\\\f(15) = -225 + 300 + 75\\\\f(15) = 150

<em><u>Thus average rate of change:</u></em>

\text {average rate of change}=\frac{f(15)-f(5)}{15-5}

\text {average rate of change}=\frac{150-150}{10}=0

Thus Average rate of change is 0

Interpretation: The crop yield did not change from year 5 to year 15.

7 0
3 years ago
Read 2 more answers
When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve
Akimi4 [234]

Answer:

5\frac{3}{10}  cans extra food is needed to feed the second cat.

Step-by-step explanation:

Given:

When chad had one cat he needed to serve 1/5 of a can of cat food each day. Now that chad adopted a second cat he needs to serve a total of 11/2 cans each day.

Now, to find the extra food is needed to feed the second cat.

Food needed for one cat = \frac{1}{5}\ of\ can.

Food needed for both one and second cat needed = \frac{11}{2}\ =5\frac{1}{2}\ cans.

Now, extra food needed to feed the second cat:

<u><em>Food needed for both one and second cat needed - food needed for one cat.</em></u>

<u><em /></u>\frac{11}{2} -\frac{1}{5}\\\\=\frac{55-2}{10} \\\\=\frac{53}{10}<u><em /></u>

<u><em /></u>=5\frac{3}{10}\ cans.<u><em /></u>

Therefore, 5\frac{3}{10}\ cans extra food is needed to feed the second cat.

5 0
3 years ago
Can u please help me? I need help with both of them. Thanks
noname [10]

Answer:

first answer is (A)

second answer is 15 ft tall



Step-by-step explanation:

if you divide 150 by 6 you get 50 so since their are 3 even and odd numbers you cut 50 in half and it'll be 25


3 0
3 years ago
Read 2 more answers
Jean-Claude equally shared a box of chocolates with two of his friends. The box weighed 9/5 pounds. How many pounds of chocolate
Anon25 [30]

I find that if you transform fractions into decimals, they become marginally easier to work with. Nine over five in decimal form is one point eight. If we divide 1.8 by three (Jean-Claude and his two friends), then we come up with the answer 0.6, which, once turned back into a fraction, would be six over ten, or three over five.

6 0
3 years ago
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