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Anit [1.1K]
3 years ago
14

Geometry. Need help on how to solve G and H

Mathematics
1 answer:
andriy [413]3 years ago
7 0

Answer:

G) tan 60 = opp / adj = 30 / x

which equals

1.7321 = 30 / x

x = 30 / 1.7321

x = 17.3200161653

H)  secant = hyp / adj

secant 30 = 16 / x

1.1547 = 16 / x

x = 16 / 1.1547

x = 13.8564

Here's a good site for trig functions :  http://www.1728.org/trigcalc.htm

Step-by-step explanation:

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Josh travels frequently. For a particular airline, it takes 20 minutes for the first bag to arrive in baggage claim after a flig
Orlov [11]

Using the uniform distribution, it is found that:

A,B) 0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.

C) 20% of the time does Josh’s bag arrive in less than 22 minutes.

--------------------------

An uniform distribution has two bounds, a and b.  

The probability of finding a value of at lower than x is:

P(X < x) = \frac{x - a}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

--------------------------

  • In the graph, we have that the distribution is uniform between 20 and 30 minutes, thus a = 20, b = 30

--------------------------

Itens a and b:

  • Above 27 minutes, thus:

P(X > 27) = \frac{30 - 27}{30 - 20} = 0.3

0.3 of the time does it take longer than 27 minutes for Josh’s bag to arrive in baggage claim.

--------------------------

Item c:

  • Less than 22 minutes, thus:

P(X < 2) = \frac{22 - 20}{30 - 20} = 0.2

0.2*100 = 20%

20% of the time does Josh’s bag arrive in less than 22 minutes.

A similar problem is given at brainly.com/question/15855314

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3 years ago
Prove a/b is less than b/a when 0 &lt; a &lt;b
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We are given that 0<a<b, which means that 0>-a>-b if you multiply it by -1, which means what's given by our inequality is true and we are done.

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The second option is the answer
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