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Anit [1.1K]
3 years ago
14

Geometry. Need help on how to solve G and H

Mathematics
1 answer:
andriy [413]3 years ago
7 0

Answer:

G) tan 60 = opp / adj = 30 / x

which equals

1.7321 = 30 / x

x = 30 / 1.7321

x = 17.3200161653

H)  secant = hyp / adj

secant 30 = 16 / x

1.1547 = 16 / x

x = 16 / 1.1547

x = 13.8564

Here's a good site for trig functions :  http://www.1728.org/trigcalc.htm

Step-by-step explanation:

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Fine the value of x for the image below
insens350 [35]

Answer:

75 = 3x

solve for x= divide 3 on both sides.

75÷3 = 25

x=25

6 0
3 years ago
(c + b + a) + (-2a - 3b + c)
inna [77]

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>2c - 2b - a</em>

▹ Step-by-Step Explanation

(c + b + a) + (-2a - 3b + c)

<u>Remove the parentheses</u>

c + b + a + (-2a - 3b + c)

<u>Collect like terms</u>

2c + b + a - 2a - 3b

<u>Final Answer</u>

2c - 2b - a

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

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7 0
3 years ago
Read 2 more answers
Can someone take 3 min for there time and help me with this please??
seropon [69]
Since the left side of the equation says f(5), then plug in 5 for x. 

So, it is: 
              
-4|5| + 3
= -20 + 3
= 23 
4 0
3 years ago
Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units. What would be the perimeters of the
Dmitriy789 [7]

Answer:

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

Step-by-step explanation:

Given - Orbet used 24 square tiles to make a rectangle. The perimeter of the rectangle is 20 units.

To find -  What would be the perimeters of the other rectangles Orbet could make using only these 24 tiles? How do the areas of the rectangles compare?

Proof -

We know that

Are of Rectangle = Length × Breadth

And Perimeter of Rectangle = 2 (Length + Breadth )

Now,

Given that,

Orbet used 24 square tiles

And perimeter of the rectangle made = 20

So,

Possible Length of rectangle = 6

Possible breadth of Rectangle = 4

Or Vice-versa.

Total number of Rectangles possible = 4

Possibilities are -  1 × 24, 2 × 12, 3 × 8, 4 × 6

Case I :

Length of rectangle = 1

Breadth of rectangle = 24

∴ Perimeter of rectangle = 2(1 + 24) = 2(25) = 50 units

Area of rectangle = 1 × 24 = 24 unit²

Case II :

Length of rectangle = 2

Breadth of rectangle = 12

∴ Perimeter of rectangle = 2(2 + 12) = 2(14) = 28 units

Area of rectangle = 2 × 12 = 24 unit²

Case III :

Length of rectangle = 3

Breadth of rectangle = 8

∴ Perimeter of rectangle = 2(3 + 8) = 2(11) = 22 units

Area of rectangle = 3 × 8 = 24 unit²

Case IV :

Length of rectangle = 4

Breadth of rectangle = 6

∴ Perimeter of rectangle = 2(4 + 6) = 2(10) = 20 units

Area of rectangle = 4 × 6 = 24 unit²

∴ we get

The perimeter of other rectangles are 50, 28, 22 units

The area of all possible rectangles are same and equals to 24 unit²

5 0
3 years ago
A professional football prospect runs 40 yards dash in 5 seconds. What is the player's average speed over this distance
Leto [7]

Answer:

average speed = 8y/s

Step-by-step explanation:

  • What is the player's average speed over this distance ?

Formula

s = d/t

d = 40 yards

t = 5 seconds

s = 40y/5s

= 8y/s

4 0
3 years ago
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