Answer:
x=2;DE,EF=9,DF=5
Step-by-step explanation:
Since DEF is isoceles, you can set the equations
x+7 and 2x+5 equal to each other
x+7=2x+5, now solve for x
-x=-2,
x=2, now plug in for each side
DE,EF=9
DF=3(2)-1=5
Answer: C
Step-by-step explanation:
5^2 + 3^2 (equals to 34) ; That's the wrong expression
It should look like this : (5+3)^2 (which equals to 64)
The minimum value of a function is the place where the graph has a vertex at its lowest point.
There are two methods for determining the minimum value of a quadratic equation. Each of them can be useful in determining the minimum.
(1) By plotting graph
We can find the minimum value visually by graphing the equation and finding the minimum point on the graph. The y-value of the vertex of the graph will be the minimum.
(2) By solving equation
The second way to find the minimum value comes when we have the equation y = ax² + bx + c.
If our equation is in the form y = ax^2 + bx + c, you can find the minimum by using the equation min = c - b²/4a.
The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term.
If this term is positive, the vertex point will be a minimum; if it is negative, the vertex will be a maximum.
After determining that we actually will have a minimum point, use the equation to find it.
Step-by-step explanation:
1. 3:4, 6:8, 9,12
So 12:15 is the same thing as 12/15 you need to simplify so 12 devided by 2 is 4 and 15 divided by 3 is 5 so question to is 4:5
