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anzhelika [568]
3 years ago
10

Which expressions are equivalent to -6 +49 +(-6q)? Choose all answers that apply:

Mathematics
2 answers:
Sidana [21]3 years ago
8 0

Answer:

C, none of them are equivalent

BECAUSE

For A, the -4q should be positive 4q to apply

For B, the 2q when distributing with the parentheses should be negative 2q to work with the expression above

Hope this helps!

mixas84 [53]3 years ago
5 0

Answer:

None of these

Step-by-step explanation:

-6 +4q +(-6q)?

Combine like terms

-6 -2q

Factor out -2

-2(q+3)

The first answer given has -6q-4q = -10q

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Find the missing height.
Arturiano [62]

Answer:

h = 12 units

Step-by-step explanation:

Area of parallelogram  = 84 square units

Height = area ÷ base

  h   = 84 ÷ 6

h = 12 units

6 0
3 years ago
justin has 7.50 more than eva and emma has 12 less than justin. together, they have a total of 63.00. how much does each person
lina2011 [118]
1st statement
Justin has 7.5 more than Eva        7.5+E
Eva = E
2nd statement
Emma has 12 less than Justin         J - 12
when J= Justin = 7.5 + E
last statement
Eva+Justin+Emma = 63
E + (7.5+E) + (7.5+E-12) =63
ADD UP
3E + 15 - 12 = 63
3E + 3 = 63
3E=63 - 3
3E=60
E=20 EMMA receives 20
J=7.5+20
J=27.5  JUSTIN receives 27.5
M=J-12
M=27.5-12
M=15.5  EMMA receives 15.5
8 0
3 years ago
Read 2 more answers
Change 7/5 to a whole number
Harlamova29_29 [7]
Write it as a mixed fraction 7/5 = 1 2/5
5 0
4 years ago
It is not d it is c i just took the test
Marina CMI [18]
Ok so nevermind i won't help


6 0
3 years ago
Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot
matrenka [14]

Answer:

\angle A \cong \angle D

Step-by-step explanation:

The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.

Thus, since John already knows that \overline{AB} \cong \overline{DE} and \overline{AC} \cong \overline{DF}, therefore, an additional information showing that the angle between \overline{AB} and \overline{DE} in ∆ABC is congruent to the angle between \overline{AC} and \overline{DF} in ∆DEF.

For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be \angle A \cong \angle D.

See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.

7 0
3 years ago
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