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3 years ago

12

I'm only good at answering not solving:,)

2 answers:

Mazyrski [523]3 years ago

7 0

Answer:

1/3 chance for even 1/3 chance for odd

Brilliant_brown [7]3 years ago

7 0

Answer:

<h2>A. 1/2 (simplified probability)</h2><h2>B. 2/3 (simplified probability)</h2>

Step-by-step explanation:

<h3>A. There are 3 even numbers in a cube which means that there are 3/6 or 1/2 probability of rolling an even number.</h3><h3 /><h3>B. The factors of 6 are: 1, 2, 3, and 6. Whick means that there is 4/6 or 2/3 probability of rolling a factor of 6.</h3><h3 />

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Could someone pls help me !

Lana71 [14]

Answer:

3

Step-by-step explanation:

24/3 is equaled to 3

if you don't know what that means its 24 divided by 3

6 0

3 years ago

Read 2 more answers

Whats the answer giving brainliest :))))) lol

n200080 [17]

Answer:

B

Step-by-step explanation:

1+1=2

But 2x has to stay the same

5 0

2 years ago

8n - (2n+11 - 54)<br>simplify

Serjik [45]

Answer:

8n - (2n + 11 - 54) =

Step-by-step explanation:

6n + 43, I used a calculator !

5 0

3 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

What is the value of 5^3¡^9

OLEGan [10]

Answer:

$125i$

Step-by-step explanation:

We want to find

$5^3i^9$

This can be rewritten as;

$5^3i^8\times i$

$5^3(i^2)^4\times i$

Recall that; $i^2=-1$

$5^3(-1)^4\times i$

We evaluate now to obtain;

$125(1)\times i=125i$

6 0

3 years ago