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3 years ago

Find the size of unknown angles

Mathematics

2 answers:

Mnenie [13.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

2∠0PQ = 36

∠OPQ = 36/2 = 18°

Join OQ,

ΔOPQ is an isosceles triangle as OP = OQ = radius

∠OQP = ∠OPQ {Angles opposite to equal sides are equal}

∠OQP = 18°

∠ORQ = 36

ΔORQ is an isosceles triangle as OR = OQ = radius

∠OQR = ∠ORQ {Angles opposite to equal sides are equal}

∠OQR = 36°

∠PQR = ∠PQO + ∠OQR

= 18 + 36

∠PQR = 54°

∠POR = 2*∠PQR {Central angle theorem}

= 2 * 54

∠POR = 108°

∠PQR + ∠PSR = 180 {Opposite angles of cyclic quadrilateral}

54 + ∠ PSR = 180

∠PSR = 180 - 54

∠PSR = 126°

∠PSR + ∠RST = 180 {linear pair}

126 + ∠RST = 180

∠RST = 180 - 126

∠RST = 54°

Paul [167]3 years ago

4 0

Step-by-step explanation:

Hope it is helpful for you

thank you

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What is the probability of being dealt exactly three of a kind (like three kings or three 7’s, etc.) in a five card hand from a

Drupady [299]

Answer:

P=0.00564

Step-by-step explanation:

From Exercise we have 52 cards.

We calculate the number of combinations to draw 5 cards from a deck of 52 cards. We get

{52}_C_{5}=\frac{52!}{5!(52-5)!}=2598960

We now count the number of favorable combinations:

{13}_C_{1} · {48}_C_{2}= 13 · \frac{48!}{2!(48-2)!}=14664

Therefore, the probabilitiy is

14664/2598960=0.00564

P=0.00564

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4 years ago

Why is the quotient of three divided by one-fifth different from the quotient of one-fifth divided by three?

aksik [14]

We write the expressions first mathematically:
three divided by one-fifth:
(3) / (1/5)
one-fifth divided by three:
(1/5) / (3)
We now use the double c method to find the results:
(3) / (1/5) = (3 * 5) / (1 * 1) = 15/1 = 15
(1/5) / (3) = (1 * 1) / (5 * 3) = 1/15 = 0.066666667
The difference between the two is:
15-0.066666667 = 14.93333333
Answer
They are different because they are inverse expressions.

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3 years ago

In a poker hand consisting of 5 cards find the probability of holding

elena-14-01-66 [18.8K]

Holding what.......? can u be more specific?

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4 years ago

The percentage of adults who currently play chess (at least once during the past year) is 12% in the UK. Suppose that in a rando

Likurg_2 [28]

Answer:

p represent the population parameter , true proportion of people who play chess in the UK

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

$z=\frac{0.1675 -0.12}{\sqrt{\frac{0.12(1-0.12)}{400}}}=2.923$

Step-by-step explanation:

Data given and notation

n=400 represent the random sample taken

X=67 represent the people who play chess

$\hat p=\frac{67}{400}=0.1675$ estimated proportion of people who play chess

$p_o=0.12$ is the value that we want to test

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p represent the population parameter , true proportion of people who play chess in the UK

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion i higher than 0.13.:

Null hypothesis: $p \leq 0.12$

Alternative hypothesis: $p > 0.12$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .