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Licemer1 [7]
3 years ago
6

Four cards are drawn in succession, without replacement from a standard deck of 52 cards. how many sets of four cards are possib

le?
Mathematics
1 answer:
balu736 [363]3 years ago
4 0
13 sets of 4 are possible

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The ratio of the number of boys to the number of girls in a choir is 5 to 4. There are 60 girls in the choir. How many boys are
Ira Lisetskai [31]

Answer:

75

Step-by-step explanation:

for every 5 boys there are 4 girls

60 / 4 = 15

15 * 5 = 75

8 0
3 years ago
5.
hoa [83]

Finding limits by direct substitution means simply means to evaluate the function at the desired value: in the first case, we have to evaluate f(x)=x^2-3 at x=0: we have

f(0)=0^2-3 = 0-3=-3

Similarly, in the second example, we have

f(x)=x^2+3x-1 \implies f(3) = 3^2+3\cdot 3-1 = 9+9-1 = 17

Going on, we have

f(x) = \dfrac{x^2-16}{x-4} = \dfrac{(x+4)(x-4)}{x-4} = x+4

And thus we have

f(4) = 4+4=8

Finally, we have

f(x) = \dfrac{x^2-2x}{x^4} = \dfrac{x(x-2)}{x^4} = \dfrac{x-2}{x^3}

So, we can't evaluate this function at 0.

6 0
4 years ago
Select all the correct answers.
Naily [24]

The correct answer is C

3 0
3 years ago
Determine the value of variables a, b, and c that make each equation true.
dybincka [34]

Corrected Question

Determine the values of a, b and c that make each equation true.

(x^a)^6=\dfrac{1}{x^{30}} \\\\(x^{-7})^{-4}=x^b\\\\(x^{-2})^c=x^{22}

Answer:

a=-5, b=28 and c=-11

Step-by-step explanation:

To solve for a,b and c, we apply the following laws of indices

\dfrac{1}{x^y}=x^{-y} \\\\(x^m)^n=x^{m X n}\\\\$If x^m=x^n,$ then m=n

Therefore

(x^a)^6=\dfrac{1}{x^{30}}\\x^{a*6}=x^{-30}\\6a=-30\\a=-5

To solve for b

(x^{-7})^{-4}=x^b\\x^{-7*-4}=x^b\\x^{28}=x^b\\b=28

To solve for c

(x^{-2})^c=x^{22}\\x^{-2*c}=x^{22}\\-2c=22\\c=-11

4 0
3 years ago
Which of the following a proportion? 2/5 = 4/25, 4/6 = 6/9, 4/3 = 6/8, 5/6 = 10/18
kaheart [24]

Answer:

4/6=6/9

Step-by-step explanation:

They can both be simplified to 2/3

7 0
3 years ago
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