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sineoko [7]
2 years ago
12

Brainlist for correct answer and 25 points for answering! Write the equation of a line that is perpendicular to y=0.25x-7 and th

at passes through the point (-6,8).

Mathematics
1 answer:
MAXImum [283]2 years ago
3 0
I’m pretty sure it’s y=-4x-16

Because the standard slope equation is y=mx+b and in perpendicular lines the slope is opposite of the slope on a parallel line. 0.25 is equal to 1/4 and the opposite of 1/4 is 4/1 but you also make it negative so it’s -4. So we have y=-4x+b and you plug in the coordinates and solve [8=-4(-6)+b and -4*-6=24 so you rewrite it as 8=24+b and 8-24=-16 and -16=b] so you plug in b and the equation is y=-4x-16

Hope this helped
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Maksim231197 [3]

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\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-39)}=\stackrel{m}{1}(x-\stackrel{x_1}{(-49)}) \\\\\\ y+39=1(x+49)\implies y+39=x+49\implies y=x+10

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