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Sergeeva-Olga [200]
4 years ago
5

TICKETS:

Mathematics
1 answer:
blsea [12.9K]4 years ago
7 0
You would need too do 5*5=25 if you did 5*7=35 that would be wrong
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What is the volume of the cone?
Rudik [331]

Answer:

16pi cm^3

Step-by-step explanation:

v =( \pi \times  {r}^{2}  \times h)  \div 3

v= (pi ·4^2 ·3): 3= 16pi

4 0
3 years ago
You talk to a friend who lives in a different state. She tells you that today it is 12 degrees below zero where she lives. You t
goblinko [34]

Answer:66

Step-by-step explanation:if its negative you subtract all of the 54 then add -12 to tha

3 0
4 years ago
Read 2 more answers
A circle is placed in a square with a side length of 18 mm, as shown below. Find the area of the shaded region.
finlep [7]
Answer: the shaded region = 69.66mm^2

Explanation:
Assume shaded region is X
Then :
X + Area of circle = area of square
X = area of square - area of circle

Find area of square:
Side length = 18mm
Area = 18 x 18 = 324

Find area of circle:
Side length of a square = the diameter of the circle = 18mm
And r(radius) = d/2 = 18/2 = 9
Area = pi x 9^2 = 254.34

Now find X
X = 324 - 254.34 = 69.66
3 0
3 years ago
A real-valued function f is said to be periodic with period T ≠ 0 if f(x + T) = f(x) for all x in the domain of f. If T is the s
Sonbull [250]

Answer:

Period T of the given function f(x) = sin(2x) + cos(4x)

   =  π

Step-by-step explanation:

Given that y(x) is a sum of two trigonometric functions. The period T of sin 2x would be (2π÷2) = π. Period T of cos4x would be (2π÷4) that is π/2

Find the LCM of π and π/2 . That would be  π. Hence the period of the given function would be π

8 0
3 years ago
Teresa deposits $800 into an account that pays simple interest at a rate of 2% per year. How much interest will she be paid in t
TiliK225 [7]

Answer:

I'll setup the problem and you can do the computation

Step-by-step explanation:

The formula for simple interest:

I = P*r*t

I = interest

P = deposit

r = interest rate per period

t = number of periods

P = $800

r = 0.02

t = 2

If you have questions, send me a comment 

3 0
3 years ago
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