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Blizzard [7]
3 years ago
13

How are the solutions to the following two equations related m+5=72 m+72=5

Mathematics
1 answer:
EastWind [94]3 years ago
6 0
To see how they are related, let us solve the two equations.

FIRST EQUATION

m + 5 = 72

\rightarrow \: m = 72 - 5

\rightarrow \: m = 67

SECOND EQUATION

m + 72 = 5

\rightarrow \: m = 5 - 72

\rightarrow \: m = - 67

Hence the solutions to the two equations are ADDITIVE INVERSE of each other.
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Solve and check the following equation algebraically. 1/2(x + 32) = -10
ANTONII [103]
Solve :
1/2(x + 32) = -10....multiply both sides by 2
x + 32 = -10 * 2
x + 32 = -20
x = -20 - 32
x = - 52 <===

check :
1/2(x + 32) = -10.....when x = -52
1/2(-52 + 32) = -10
1/2(-20) = -10
-20/2 = -10
-10 = -10 (correct)

8 0
3 years ago
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If DE = 37 cm and EF = 16 cm, then what are the possible lengths for DF so that DE,EF, and DF can form a triangle? Explain your
chubhunter [2.5K]

Answer:

The length of DF must be between 21 and 53.

Step-by-step explanation:

In a triangle, the length of two sides added together must exceed the length of the 3rd side. So, since EF is the shortest of the two givens, we know that EF + DF must be greater than DE. So we can plug in these numbers to find the minimum.

EF + DF > DE

16 + DF > 37

DF > 21

Now, for the upper maximum, we know that the two given lengths must be greater than the length of DF. So again, we can solve for the maximum using the amounts.

DE + EF > DF

37 + 16 > DF

53 > DF

With these two in mind, we know that DF must be between 21 and 53

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3 years ago
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