N₂ + 3H₂ ⇄ 2NH₃ + heat
In the given equilibrium, we notice that the heat is on the right. which means that if the heat requirements don't meet, the reactants on the right will no longer react due to the lack of heat
but because the reactants on the left don't have such weaknesses, they will keep reacting hence producing more and more ammonia until a new equilibrium is reached
where there will be more ammonia and less nitrogen and hydrogen as compared to the equilibrium we had initially
Answer:
B) Ksp = 3.7 E-11
Explanation:
CaF2 ↔ Ca2+ + 2F-
S S 2S,,,,,,,,,,,,,,,in the equilibrium
⇒ Ksp = [ Ca2+ ] * [ F- ]²
⇒ Ksp = S * ( 2S )²
⇒ Ksp = 4S³
⇒ Ksp = 4 * ( 0.00021 )³
⇒ Ksp = 4 * 9.261 E-12
⇒ Ksp = 3.704 E-11
22.6 x 10^5 J
‘Heat of vaporization’ is the amount of ‘heat’ required to convert '1g' of mass of a liquid to vapor. Normal “boiling point of water” is 100 C. The heat of vaporization at this temperature is 2260 J/g. It means 2260 J/g of heat is required to convert ‘1g of water’ to 1g of vapor at 100 C. So to convert 1 kg of mass of water or 1000g of water we require 22.6 x 10^5 J of heat.
<u>Answer:</u> The volume of liquid in liters is 2.5812 L.
<u>Explanation:</u>
Density of an object is defined as the ratio of its mass and volume. The chemical equation representing density of an object is:
We are given:
Mass of liquid = 3.02 kg = 3020 g (Conversion factor: 1kg = 1000 g)
Density of liquid = 
Putting values in above equation, we get:
Converting this into liters, we use the conversion factor:
So, 
Hence, the volume of the liquid is 2.5812 L.
