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3 years ago

a scientist uses 68 grams of CaCo3 to prepare 1.5 liters of solution. what is the molarity of this solution?

Chemistry

1 answer:

victus00 [196]3 years ago

7 0

Answer: 0.4533mol/L

Explanation:

Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol

68g of CaCO3 dissolves in 1.5L of solution.

Xg of CaCO3 will dissolve in 1L i.e

Xg of CaCO3 = 68/1.5 = 45.33g/L

Molarity = Mass conc.(g/L) / molar Mass

Molarity = 45.33/100 = 0.4533mol/L

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At 373.15K and 1 atm, the molar volume of liquid water and steamare 1.88 X 10-5 m3 and 3.06 X 10-2m3, respectively. Given that t

professor190 [17]

Answer The value of $\Delta H$ and $\Delta U$ is, 40.79 kJ and 37.7 kJ respectively.

Explanation :

Heat released at constant pressure is known as enthalpy.

The formula used for change in enthalpy of the gas is:

$\Delta Q_p=\Delta H=40.79kJ/mol$

Now we have to calculate the work done.

Formula used :

$w=-P\Delta V\\\\w=-P\times (V_2-V_1)$

where,

w = work done = ?

P = external pressure of the gas = 1 atm

$V_1$ = initial volume = $1.88\times 10^{-5}m^3=1.88\times 10^{-5}\times 10^3L=1.88\times 10^{-2}L$

$V_2$ = final volume = $3.06\times 10^{-2}m^3=3.06\times 10^{-2}\times 10^3L=3.06\times 10^{1}L$

Now put all the given values in the above formula, we get:

$w=-(1atm)\times (3.06\times 10^{1}-1.88\times 10^{-2})L$

$w=-30.5812L.atm=-30.5812\times 101.3J=-3097.87556J=-3.09\times 10^3J=-3.09kJ$

Now we have to calculate the change in internal energy.

$\Delta U=q+w$

$\Delta U=40.79kJ+(3.09kJ)$

$\Delta U=37.7kJ$

Thus, the value of $\Delta H$ and $\Delta U$ is, 40.79 kJ and 37.7 kJ respectively.

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2 years ago

How many liters of a 0.50 solution are needed to give 3.5 moles of solute

sertanlavr [38]

0.50 Molar means 0.50 moles/liter
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2 years ago

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zavuch27 [327]

N2 stands for nitrogen.
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3 years ago

Physical science!!! please help

IgorLugansk [536]

Answer:

The correct answer is : No, because there are 4 hydrogen atoms on the reactants side and 2 on the products side.

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3 years ago