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topjm [15]
3 years ago
10

What is weatherization?

Chemistry
2 answers:
kkurt [141]3 years ago
6 0

Answer:

Weatherization or weatherproofing is the practice of protecting a building and its interior from the elements, particularly from sunlight, precipitation, and wind, and of modifying a building to reduce energy consumption and optimize energy efficiency.

miv72 [106K]3 years ago
5 0

Answer: to make (something, such as a house) better protected against winter / weather.

Explanation:

weathernization is something made that is protected against weather.

                              <em>I HOPE THIS HELPS.!!!!</em>

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Where do the sun rays hit Earth's surface nearly at right angles ​
hoa [83]

Answer:

The Sun Ray's hit earths surface at Earths Equator

8 0
3 years ago
What is the pH of a 0.025 M HCl solution?<br> 12.4<br> 1.6<br> 2.5<br> 05
attashe74 [19]

Answer:  pH is 1.6

Explanation: Explanation: HCl is strong acid and it protolyzes totally:

HCl + H2O  ⇒ H3O+ + Cl-

Concentrations are same:  [H3O+] = c(HCl)

pH = - log[H3O+] = - log(0.025) = 1.60

7 0
3 years ago
A sample of lsd (d-lysergic acid diethylamide, c24h30n3o) is added to some table salt (sodium chloride) to form a mixture. given
spin [16.1K]
1) All the CO2 comes from the C24 H30 N3 O

2) To balance C from CO2 with C from C24, the ratio of cC24 H30 N3 O to CO2 is 24 / 1

3) Convert 1.20 g of CO2 to number of moles

number of moles = mass in grams / molar mass

mass = 1.20 g

molar mass = 12.01 g/mol + 32.00 g/mol = 44.01 g/mol

number of moles = 1.2 g / 44.01 g/mol = 0.0273 mol

4) proportion

1 mol C24 H30 N3 O / 24 mol CO2 = x / 0.0273 mol CO2

=> x = 0.0273 mol CO2 * 1 mol C24H30N3O / 24 mol CO2 = 0.00114 mol C24H30N3O

5) Convert 0.00114 mol C24H30N3O to grams

molar mass = 376.5 g/mol

mass = 0.00114 mol * 376.5 g/mol = 0.429 g

6) mass percent in the mixture

mass percent = (mass of lsd / mass of mixture) * 100 = (0.429g / 1.0g) * 100 = 42.9%

Answer: 42.9%


6 0
3 years ago
For the following set of pressure/volume data, calculate the new volume of the gas sample after the pressure change is made. Ass
faust18 [17]

Answer:

a. 121 ml, b. 253 ml and c. 2.57 L.

Explanation:

The new volume can be calculated by using the Boyle's law equation:  

P1V1 = P2V2

In the equation, P1 and P2 are the initial and final pressures and V1 and V2 are the initial and final volumes for a real gas at constant temperature.  

a) Based on the given information, P1 = 755 mmHg, V1 = 125 ml, P2 = 780 mm Hg and V2 will be,  

V2 = P1V1/P2

V2 = 755 mmHg × 125 ml/780 mmHg

V2 = 121 ml

b) Based on the given information, P1 = 1.08 atm, V1 = 223 ml, P2 = 0.951 atm and V2 will be,  

V2 = P1V1/P2

V2 = 1.08 atm × 223 ml/0.951 atm

V2 = 253 ml

c) Based on the given information, P1 = 103 kPa, V1 = 3.02 L, P2 = 121 kPa and V2 will be,  

V2 = P1V1/P2

V2 = 103 kPa × 3.02 L/121kPa

V2 = 2.57 L

3 0
3 years ago
Ms. Block's students are studying chemical reactions. A classic reaction occurs when a metal is added to hydrochloric acid. Migu
g100num [7]

Answer:

the boys should cover the end of the test tube to a ballon

Explanation:

5 0
3 years ago
Read 2 more answers
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