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Fudgin [204]
2 years ago
11

For the function f defined below, evaluate f (3,7), f(4,4), and f (1,5)

Mathematics
1 answer:
eimsori [14]2 years ago
3 0

Answer:

Step-by-step explanation:

f(3,7)=\frac{3+7}{2(3)+7}=\frac{10}{13}\\f(4,4)=\frac{4+4}{2(4)+4}=\frac{8}{12}=\frac{2}{3}\\f(1,5)=\frac{1+5}{2(1)+5}=\frac{6}{7}

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(x^4)^3=(x^3)^4 true or false
telo118 [61]

Step-by-step explanation:

(x^4)^3=(x^3)^4 , true

=> x^(4×3) = x^(3×4) = x^12

13^4 x 13^7= (13^4)^7, false

13^(4+7) = 13^11

(13^4)^7 = 13^(4×7) = 13^28

y^5 x y^0/y^3=(y^2)^1 , true

y^5 x y^0/y^3 = y^(5+0-3) = y^2

(y^2)^1 = y^(2×1) = y^2

q^0 x q^5/q^2=(q^3)^2/q^3, true

q^0 x q^5/q^2= q^(0+5-2)= q^3

(q^3)^2/q^3 = q^(3×2-3) = q^3

6 0
2 years ago
Read 2 more answers
Last month, you worked 41 hours the first week, 49 hours the second week, 48 hours the third week, and 46 hours the last week. F
inysia [295]

Answer:

46 hours

Step-by-step explanation:

1. add all the hours you've worked (41+49+48+46=184)

2. divide the sum by the number of weeks (184/4=46)

5 0
3 years ago
I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
elena-14-01-66 [18.8K]

Hello,

m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\

cos(30^o)=\dfrac{\sqrt{3} }{2} \\

In the triangle ABC,

cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\

sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}

In the triangle ACB,

cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\

6 0
3 years ago
What is the equation of the line that passes through points (15,9) and (-2,9)
Vikki [24]

Answer:

y=9

Step-by-step explanation:

Slope: 9-9/-2-15=0

Therefore, y=0x+b

Plug values in: 9=0(-2)+b

0+b=9

b=9

Therefore, equation is y=9

7 0
3 years ago
Please see below!! Thank you so much in advance :)
stellarik [79]

Answer:

a) x = -1.9, 1.05

b) x = -3, 0, 2

Explanation:

I hope it's correct

7 0
2 years ago
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