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igor_vitrenko [27]

2 years ago

15

The teacher plans to buy pillowcases for his students. Each student needs 55 cm of material and there are 83 students. how many

does the teacher need to buy for his students ???

1 answer:

laiz [17]2 years ago

5 0

Answer:

4565 cm

Step-by-step explanation:

55 * 83

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The arch of a bridge forms the upper half of an ellipse. The arch is 6 meters above the 20-meter-wide river. Write an equation f

aksik [14]

Answer:

$\frac{x^2}{36} + \frac{y^2}{100} = 1$

Step-by-step explanation:

Required

The equation of the ellipse

This is calculated as:

$\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$

Where:

$b =6$ ---- height

$a = 0.5 * 20 =10$ --- width

So:

$\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$

$\frac{x^2}{6^2} + \frac{y^2}{10^2} = 1$

$\frac{x^2}{36} + \frac{y^2}{100} = 1$

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2 years ago

Solve the inequality.<br> 6x + 10 + 10x < 4(4x + 3)

Elena L [17]

Answer:

X = all #'s

why?

6x+10+10x < 4(4x+3)

Combined liked terms

16x + 10 < 16x +12

you can see that there is X on both sides and the lowest one has a +10 and the highest has a +12 so it will always be greater by 2

5 0

2 years ago

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Consider the enlargement of the rectangle.

Drupady [299]

Answer:

2.5

Step-by-step explanation:

i did it and got it right

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3 years ago

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What is 9.468 rounded to the nearest tenth

Ivan

9.47 i think thats the answer

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3 years ago

Which rule describes the composition of transformations that maps pre- image ABCD to final image A“B“C“D“?

Svetlanka [38]

Answer:

1. Reflection across the x-axis

2. Translation 6 units to the left and 1 unit up

Step-by-step explanation:

The quadrilateral ABCD has its vertices at points A(3,5), B(6,5), C(4,1) and D(1,1).

1. Reflect quadrilateral ABCD across the x-axis. This reflection has the rule:

$(x,y)\rightarrow (x,-y),$

then

$A(3,5)\rightarrow A'(3,-5)\\ \\B(6,5)\rightarrow B'(63,-5)\\ \\C(4,1)\rightarrow C'(4,-1)\\ \\D(1,1)\rightarrow D'(1,-1)$

2. Translate quadrilateral ABCD 6 units to the left and 1 unit up. This translation has the rule:

$(x,y)\rightarrow (x-6,y+1),$

then

$A'(3,-5)\rightarrow A''(-3,-4)\\ \\B'(6,-5)\rightarrow B''(0,-4)\\ \\C'(4,-1)\rightarrow C''(-2,0)\\ \\D'(1,-1)\rightarrow D''(-5,0)$

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3 years ago

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