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2 years ago

The table below shows the number of yards the students walked during recess today.

1 answer:

3 0

It’s 40 minutes cause it’s the farthest Which impact did WWII have on the U.S?
A. The U.S. had to rebuild much of its own infrastructure due to the damages of the War
B. The U.S. had one of the highest death tolls of the War
C. The U.S. decided to not get involved in any
future wars
D. The U.S. experienced large economic growth as a result of their wartime economy

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What is the answer/ how do i answer <br> 25 = x + 7

Phoenix [80]

Just subtract 7 from 25. it is 18

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3 years ago

Read 2 more answers

Consider the hypothesis test H0: μ1= μ2 against H1: μ1.Suppose that the sample sizes aren1 = 15 and n2 =μ2. Assume thatσ21 = σ22

torisob [31]

Answer:

see attachments

Step-by-step explanation:

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3 years ago

A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e

My name is Ann [436]

Answer:

$\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)} \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$

Step-by-step explanation:

If the system contains $n$ atoms, we can arrange $r$ quanta of energy in

$\binom{n}{r} = \dfrac{n!}{r!(n-r)!}$

ways.

$\mathbf{a)}$

In this case,

$n = 2, r=1$ .

Therefore,

$\binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2$

which means that we can arrange 1 quanta of energy in 2 ways.

$\mathbf{b)}$

In this case,

$n = 20, r=10$ .

Therefore,

$\binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756$

which means that we can arrange 10 quanta of energy in 184 756 ways.

$\mathbf{c)}$

In this case,

$n = 2 \times 10^{23}, r = 10^{23}$ .

Therefore, we obtain that the number of ways is

$\binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}$