A. 48 = 12 + 20 + x
If you use this equation then you can do 12 + 20 = 32 and then you can do 48 - 32 = 16 so x = 16
Answer:
The correct option is B.
Step-by-step explanation:
According to AAS congruence rule, two triangles are congruent if two angles and a non included side are congruent to corresponding angles and side of another triangle.
We need two angles and a non included side, to use AAS postulate.
In option A, two sides and their inclined angle are congruent, therefore these triangles are congruent by SAS postulate and option A is incorrect.
In option B, two angles and a non included side are congruent, therefore these triangles are congruent by AAS postulate and option B is correct.
In option C, two angles and their included side are congruent, therefore these triangles are congruent by ASA postulate and option C is incorrect.
In option D, all sides are congruent, therefore these triangles are congruent by SSS postulate and option D is incorrect.
Answer:
60.15 km
Step-by-step explanation:
If 6 km on the map represents 4 mi on land, then we'd get the answer by using the relation
6 km -> 4 mi
x km -> 40.1 mi
Where x km is the length on the map we're looking for. If we cross multiply
6 * 40.1 = 4x
240.6 = 4x
x = 240.6/4
x = 60.15 km.
That is the length we're looking for
Answer:
Step-by-step explanation:
x+(x+1)+(x+2)+(x+3)=-210
x+1x+1+1x+2+1x+3=-210
4x+6=-210
4x=-210-6
4x/4x=-216/4
x=54
240 homes in the county are between $175,000 and $225,000.
The image attached is associated with this question and m in it refers to the mean value which is $225000 here and d refers to the standard deviation which is $25000 here.
Now since m= $225000
and $175000= $225000-$50000= $225000-(2* $25000)= m-2d
Thus, as per the image area covered between m and m-2d= $225000
and $175000 is (34%+14%)of 500 homes= 68% of 500= 240 homes, is the answer.
A random variable X is said to follow a normal distribution if its parameters are mean and standard deviation. Every other distribution can be reduced to a normal distribution.
Learn to know more about normal distributions on brainly.com/question/4079902
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