E^3x.cos4x.sin2x hii please solv this you have to differentiate
1 answer:
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Answer:
The answer is
Step-by-step explanation:
We must find a solution where
Consider the Left Side:
First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get
Which equals
Add the fractions
Simplify the right side by multiplying the fraction
Set both fractions equal to each other
Since the denomiator are equal, we must set the numerator equal to each other
Answer:
see explanation
Step-by-step explanation:
The n th term ( explicit formula ) of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₁₂ = - 95 and a₃₇ = - 270 , then
a₁ + 11d = - 95 → (1)
a₁ + 36d = - 270 → (2)
Subtract (1) from (2) term by term to eliminate a₁
25d = - 175 ( divide both sides by 25 )
d = - 7
Substitute d = - 7 into (1) and solve for a₁
a₁ + 11(- 7) = - 95
a₁ - 77 = - 95 ( add 77 to both sides )
a₁ = - 18 , thus
= - 18 - 7(n - 1) = - 18 - 7n + 7 = - 7n - 11
= - 7n - 11 ← explicit formula
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The recursive formula allows a term in the sequence to be found by adding the common difference d to the previous term, thus
=
- 7 with a₁ = - 18 ← recursive formula