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2 years ago

E^3x.cos4x.sin2x hii please solv this you have to differentiate

Mathematics

1 answer:

finlep [7]2 years ago

6 0

Answer:

$y = e^{3x}.cos4x.sin2x$

$=> y' =- 3e^{3x}.4sin4x.2cos2x=-24.e^{3x}.sin4x.cos2x$

$dy=y'.dx => dy = -24e^{3x}.sin4x.cos2x.dx$

Step-by-step explanation:

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Read 2 more answers

E^3x.cos4x.sin2x hii please solv this​ you have to differentiate

E^3x.cos4x.sin2x hii please solv this you have to differentiate