2 years ago

E^3x.cos4x.sin2x hii please solv this you have to differentiate

1 answer:

finlep [7]2 years ago

6 0

Answer:

$y = e^{3x}.cos4x.sin2x$

$=> y' =- 3e^{3x}.4sin4x.2cos2x=-24.e^{3x}.sin4x.cos2x$

$dy=y'.dx => dy = -24e^{3x}.sin4x.cos2x.dx$

Step-by-step explanation:

You might be interested in

satela [25.4K]

Substitue what y equals for y and solve.

$-4x+7(3x+15)=20 \\-4x+27x+105=20 \\23x=-85 \\x=-\boxed{\frac{85}{23}}$

Hope this helps.

3 0

2 years ago

adell [148]

Your answer is x = 3

5 0

2 years ago

-BARSIC- [3]

Answer:

dont scam people

Step-by-step explanation:

4 0

2 years ago

hichkok12 [17]

60/500=?/100
60/5=12
12/100
12%.

3 0

3 years ago

Lubov Fominskaja [6]

Answer:

2700

Step-by-step explanation:

3 0

2 years ago

E^3x.cos4x.sin2x hii please solv this​ you have to differentiate