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grandymaker [24]
3 years ago
8

HELP ME NOW!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Monica [59]3 years ago
4 0

Answer:

An $11 tip is 20%

Step-by-step explanation:

You have to multiply the percentage and the money amount, the equation would look like so 54.65 x .20= 109300 <----Is the answer you get but you have to move the decimal 4 places because of where the decimals are in the multipliers. So you get 10.9300 or $10.93 and rounded to the nearest dollar would be $11

Hope this helps if so please mark brainliest ;D

mario62 [17]3 years ago
4 0

Answer:

An $11 tip is 20%

Step-by-step explanation:

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Solve (t-5) = 2 where t is a real number.<br> Simplify your answer as much as possible.
In-s [12.5K]

Answer:

7

Step-by-step explanation:

T-5=2 2+5=7

7 0
4 years ago
Given the graphed function below, which of the following ordered pairs are found on the inverse function?
Dmitrij [34]

Answer:

Its C (-9,-2)(-2,-1)(-1,0)(0,1)(7,2)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
P(x) = x^4+ax^3-x^2+bx-12 has factors of (x-2) and (x+1). Solve the equation P(x)=0​
Feliz [49]

Answer:

because P(x) has factors of (x-2) and (x+1) => x = 2 and x = -1 are the solutions of P(x)

so we have:

\left \{ {{2^{4}+2^{3}a-2^{2}+2b-12   =0} \atop {1-a-1-b-12=0}} \right.\\=>\left \{ {{8a+2b=0} \atop {a+b=-12}} \right.\\\left \{ {{4a+b=0} \atop {a+b=-12}} \right.\\\left \{ {{a=4} \atop {b=-16}} \right.

=> P(x)=x^{4} + 4x^{3}-x^{2} -16x-12

With P(x) = 0

=> x^{4}+4x^{3}-x^{2} -16x-12 = 0

=> ........

Step-by-step explanation:

5 0
3 years ago
On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and curves up and increases in quadrant 1.
shepuryov [24]

Answer:

The domain of the function i.e. the value of x can be any real number and the range of the function is y > 0.

Step-by-step explanation:

On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and curves up and increases in quadrant 1.

Therefore, as x tends to - ∞, the y-value tends to 0 but not equal to zero and as x tends to +∞, the y-value also tends to +∞.

Hence, the domain of the function i.e. the value of x can be any real number and the range of the function is y > 0. (Answer)

7 0
3 years ago
25 points
igor_vitrenko [27]
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