Answer:
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Step-by-step explanation:
The given initial value problem is;

Let
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Differentiating both sides of equation (1) with respect to
, we obtain:
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Differentiating both sides of equation (2) with respect to
gives:
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From equation (1),

Putting t=0 into equation (2) yields

Also putting t=0 into equation (3)

The system of first order equations is:
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15: M= 2
B= -5
Slope intercept form= y=2x-5
16: y=5/8x + 1/2
there are 10 million grains in that bag of sand this is because one grain equals to 10 power -3 what about 10 kg you change it into grams then you cross multiply and get the answer