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3 years ago

9

How many terms are in the polynomial abcd + e - h 2? two

1 answer:

a_sh-v [17]3 years ago

7 0

There are three terms in the polynomial.

Step-by-step explanation:

Given that,

A polynomial, $abcd + e - h^ 2$ .

To find,

The number of terms in the polynomial.

Solution,

The number of terms in the polynomial are the number of unlike expressions that are separated by a minus or plus.

We have, $abcd + e - h^ 2$ .

The terms are :

$abcd$ , $e$ , $-h^2$

It implies that there are three terms in the given polynomial.

Reference,

brainly.com/question/4458265

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Someone plz help me T^T

IRINA_888 [86]

Answer:24 red 48 yellow and 24 white.

Step-by-step explanation:

Math

8 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

R 2x-6+3=6x-5 please help

frozen [14]

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$2x - 6 + 3 = 6x - 5$

$2x - 3 = 6x - 5$

$6x - 5 = 2x - 3$

Add sides 5

$6x - 5 + 5 = 2x - 3 + 5$

$6x = 2x + 2$

Subtract sides 2x

$- 2x + 6x = - 2x + 2x + 2$

$4x = 2$

Divide sides by 4

$\frac{4x}{4} = \frac{2}{4} \\$

$x = \frac{1}{2} \\$

_________________________________

CHECK :

$2( \frac{1}{2} ) - 3 = 6( \frac{1}{2} ) - 5 \\$

$1 - 3 = 3 - 5$

$- 2 = - 2$

Thus the solution is correct....

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3 0

3 years ago

Read 2 more answers

A father is giving his child a 30-inch long softball bat for her birthday.He has a rectangular box that has the dimensions of 5

Colt1911 [192]

I think it will because 5 × 6 × 25 = 750 in.

The bat is 30 in.

So, I think it will fit.

Hope this helped☺☺

8 0

3 years ago

Anyone know? I need help it’d be cool if someone gave the answer

photoshop1234 [79]

Answer: 19 units

Step-by-step explanation:

Count from A down then the left until you reach B.

8 0

3 years ago