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Ber [7]
3 years ago
9

How many terms are in the polynomial abcd + e - h 2? two

Mathematics
1 answer:
a_sh-v [17]3 years ago
7 0

There are three terms in the polynomial.

Step-by-step explanation:

Given that,

A polynomial, abcd + e - h^ 2.

To find,

The number of terms in the polynomial.

Solution,

The number of terms in the polynomial are the number of unlike expressions that are separated by a minus or plus.

We have, abcd + e - h^ 2.

The terms are :

abcd, e,-h^2

It implies that there are three terms in the given polynomial.

Reference,

brainly.com/question/4458265

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Which of the following is equal to the rational expression when x ≠ -4 or 16?
stepan [7]

Answer:

C

Step-by-step explanation:

Given

\frac{x^2-16}{(x-16)(x+4)}

The numerator is a difference of squares

x² - 16 = (x - 4)(x + 4)

= \frac{(x-4)(x+4)}{(x-16)(x+4) } ← cancel the common factor (x + 4) on numerator/ denominator

= \frac{x-4}{x-16} → C

3 0
3 years ago
Consider line segment AB whose endpoints are (1, 4) and (4, 8). If this segment is dilated by a scale factor of 4 centered at th
gulaghasi [49]

Answer:

The length of the new segments A'B' is 20 units ⇒ answer C

Step-by-step explanation:

* <em>Lets revise the dilation</em>

- A dilation is a transformation that changes the size of a figure.  

- It can become larger or smaller, but the shape of the  figure does

 not change.  

- The scale factor, measures how much larger or smaller the image

 will be

- If the scale factor greater than 1, then the image will be larger

- If the scale factor between 0 and 1, then the image will be smaller

* <em>Lets solve the problem</em>

- line segment AB whose endpoints are (1, 4) and (4, 8) is dilated by

 a scale factor of 4 and centered at the origin

∵ The scale factor is 4 and it is greater than 1

- The length of the image of line segment AB will enlarged by the

   scale factor 4

∴ A'B' = 4 AB

* <em>Lets find the length of AB by using the rule of the distance</em>

∵ d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

∵ A = (x_{1},y_{1}) and B = (x_{2},y_{2})

∵ A = (1 , 4) and B = (4 , 8)

∴ (x_{1},y_{1})=(1 , 4) and (x_{2},y_{2})=(4 , 8)

∵ AB = \sqrt{(4-1)^{2}+(8-4)^{2}}=5

∴ AB = 5 units

∵ A'B' = 4 AB

∴ A'B' = 4 × 5 = 20

∴ The length of the new segments A'B' is 20 units

8 0
3 years ago
Simplify the expression 6C5.<br> a.6.<br> b. 24<br> C. 30<br> d. 720
Lana71 [14]
<h3>Answer:  A) 6</h3>

=====================================================

Explanation:

Plug n = 6 and r = 5 into the nCr combination formula

_n C _r = \frac{n!}{r!*(n-r)!}\\\\_6 C _5 = \frac{6!}{5!*(6-5)!}\\\\_6 C _5 = \frac{6!}{5!*1!}\\\\_6 C _5 = \frac{6*5*4*3*2*1}{5*4*3*2*1*1}\\\\_6 C _5 = \frac{720}{120}\\\\_6 C _5 = 6\\\\

Or you could use the shortcut

_n C _{n-1} = n\\\\

Yet another path you could take is to use Pascal's Triangle. Locate the row that starts with 1,6,... and then locate the second to last item. That value in the triangle is 6.

A real world interpretation is to consider having 6 people and you are selecting 5 of them to form a group where order doesn't matter. How many ways are there to do this? Well there are 6 such ways because there are 6 ways to leave someone out of the group.

8 0
2 years ago
What is the solution to the following system of equations?
Minchanka [31]
<span>The correct answer is option B. i.e. (1,-10) two equations are y = -x^2 - 5x - 4 and y = -x^2 + 9x - 18. Now, equating both the equations we get, -x^2 - 5x - 4 = -x^2 + 9x - 18 or 14 x= 14 or x = 1. Now, y = -1 -5 -4 = -10.</span>
5 0
4 years ago
Read 2 more answers
Nhich equation results from taking the square root of both sides of (x+9)2=25
ale4655 [162]

Answer:

square root of 25=5 and square root of (x+9)=(x+9) so the answer is.... x+9=+-5

Step-by-step explanation:

3 0
3 years ago
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