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Ber [7]
3 years ago
9

How many terms are in the polynomial abcd + e - h 2? two

Mathematics
1 answer:
a_sh-v [17]3 years ago
7 0

There are three terms in the polynomial.

Step-by-step explanation:

Given that,

A polynomial, abcd + e - h^ 2.

To find,

The number of terms in the polynomial.

Solution,

The number of terms in the polynomial are the number of unlike expressions that are separated by a minus or plus.

We have, abcd + e - h^ 2.

The terms are :

abcd, e,-h^2

It implies that there are three terms in the given polynomial.

Reference,

brainly.com/question/4458265

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.50 × N = 30
Divide both sides by .50
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3 years ago
Find the distance between the points given. (-3, 2) and (9, -3) A √37 B √61 C 13​
Kitty [74]

Answer:

\huge{ \fbox{ \sf{13 \: units}}}

Option C is correct.

Step-by-step explanation:

\star{ \sf{ \: Let \: the \: points \: be \: a \: and \: b}}

\star{ \sf{ \: let \: A(-3, 2) \: be \: (x1 \:, y1) \:  and  \: B(9, -3) \: be \: (x2 \:, y2) }}

\underline{ \sf{Finding \: the \: distance \: between \: the \: given \: points}} :

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{  \sqrt{ {(9 - ( - 3))}^{2} +  {( - 3 - 2)}^{2}  } }}

\mapsto{ \sf{ \sqrt{ {(9 + 3)}^{2}  +  {( - 3 - 2)}^{2} }}}

\mapsto{ \sf{ \sqrt{ {(12)}^{2}  +  {( - 5)}^{2} } }}

\mapsto{ \sf{ \sqrt{144 + 25}}}

\mapsto{ \sf{ \sqrt{169} }}

\mapsto{ \sf{ \sqrt{ {(13)}^{2} } }}

\mapsto{ \sf{ 13 \: units}}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

7 0
3 years ago
1/7 (x-3) = 5/7 ? solve for x.
yuradex [85]
1/7 (x - 3) = 5/7
1/7x - 3/7 = 5/7
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1/7x = 8/7
1/7x(7) = 8/7(7)
X = 56/7
X = 8
4 0
3 years ago
Solve for d: s=d/t<br> please help
nika2105 [10]
Where is the equation?
6 0
3 years ago
Read 2 more answers
Blank times 6/12 = 1/10
Goryan [66]
2/10 is the answer.
8 0
3 years ago
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