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3 years ago

If you rolled a die, what is the probability that you would roll an odd number

Mathematics

2 answers:

weeeeeb [17]3 years ago

6 0

Answer:

P = 3/6.

Step-by-step explanation:

there are three odd numbers and three even numbers on a 6-sided die. the probability of rolling an odd number is 50%, which can be converted to 1/2, or 3/6. hope this helps

- Zombie

Triss [41]3 years ago

6 0

Answer:

3/6

Step-by-step explanation:

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When six is subtracted from five times a number, the result is 9

lozanna [386]

You do 9=5y-6. And then solve for y. It’s is 3.

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2 years ago

Tracey paid $170 for an item that was originally priced at $580. What percent of the original price did Tracey pay? Round your a

Katarina [22]

You can use the is/of = %/100 formula, and just simply input the values.
Therefore, 170/580=%/100
580x=170,000
29.31

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3 years ago

Point C ∈ AB , AB = 30m. Point C is 1.5 times farther from point A than from point B. Find AC and CB.

Shtirlitz [24]

let's say that C is "x" units farther from B, that means that CB = x, and therefore AC = 1.5x.

$\bf \underset{\leftarrow ~~30~~\to}{\boxed{A}\stackrel{1.5x}{\rule[0.35em]{18em}{0.25pt}}C\stackrel{x}{\rule[0.35em]{10em}{0.25pt}}\boxed{B}}
\\\\\\
AB=AC+CB\implies \stackrel{AB}{30}=\stackrel{AC}{1.5x}+\stackrel{CB}{x}\implies 30=2.5x
\\\\\\
\cfrac{30}{2.5}=x\implies 12=x
\\\\[-0.35em]
~\dotfill\\\\
AC=1.5(12)\implies AC=18~\hspace{8em} CB=x\implies CB=12$

8 0

3 years ago

I am in fourth grade and I have no idea how to find whole numbers between a fraction can you show me?

allsm [11]

Answer:

To find a a fraction of a whole number, you multiply the numerator of the fraction by the given number and then divide the product by the denominator of the fraction

Solved example for finding a fraction of a whole number:

Find 1/3 of 21.

To find 1/3 of 21, we multiply the numerator 1 by the given whole number 21 and then divide the product 21 by the denominator 3.

1/3 × 21 = 1 × 21/3 = 21/3 = 7

So, 1/3 of 21 = 7.

1/3 of 21 is 7

5 0

2 years ago

Read 2 more answers

Give an example of each of the following or explain why you think such a set could not exist.

Oksanka [162]

Answer:

a.No

b.No

c.No

Step-by-step explanation:

a.No,Such set does not exist .A set of natural numbers is N

Every point of this set is an isolated point but no accumulation point

Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set

$(a-\epsilon,e+\epsilon)\cap S-{a}\neq\phi$

Isolated point : it is defined as that point a of set S which neighborhood does not contain any other point of set except itself

$(a-\epsilon0,a+\epsilon)\cap S-{a}=\phi$

Interior point of set :Let $a\in S$ .Then a is called interior point of set when its neighborhood is a subset of set S.

$a\in(a-\epsilon,e+\epsilon)\subset S$

When a set is uncountable then interior point exist it is necessary for interior points existance .

Boundary points :Let $a\in S$ .If every non empty neighborhood of a intersect S and complement of S.

Every member of a set is a boundary point

b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers

c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of boundary point and isolated point

6 0

3 years ago