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Fed [463]
3 years ago
5

Polynomial Equation question(Screenshot included)

Mathematics
1 answer:
Illusion [34]3 years ago
6 0

y = {x}^{3}  - 4 {x}^{2}  - 45x \\ y = x( {x}^{2}  - 4x - 45) \\ y = x(x + 5)(x - 9) \\ x = 0, - 5,9
So, to find our x-intercepts, y must be zero
0 = x \\  \\ 0 = (x + 5) \\  - 5 = x \\  \\ 0 = (x - 9) \\ 9 = x
ANSWER: (0,0) (-5.0) (9,0) are your x-intercepts
You might be interested in
The sixth term is 22 and the common difference is 6 what is the 15th term?
matrenka [14]

Answer:

76

Step-by-step explanation:

I made a chart to simplify it

1 | -8

2| -2

3| 4

4| 10

5| 16

6| 22

7| 28

8| 34

9| 40

10| 46

11| 52

12| 58

13| 64

14| 70

15| 76

5 0
3 years ago
Let a be a rational number and b be an irrational number. Which of the following are true statements?(there is more than 1 answe
kramer
<span>A.) the sum of a and b is never rational.
This is a true statement. Since an irrational umber has a decimal part that is infinite and non-periodical, when you add a rational number to an irrational number, the result will have the same infinite non periodical decimal part, so the new number will be irrational as well.

</span><span>B.) The product of a and b is rational
This one is false. Zero is a rational number, and when you multiply an irrational number by zero, the result is always zero.

</span><span>C.) b^2 is sometimes rational
This one is true. When you square an irrational number that comes from a square root like </span>\sqrt{2}, you will end with a rational number: ( \sqrt{2} )^{2}=2, but, if you square rationals from different roots than square root like \sqrt[3]{2}, you will end with an irrational number: \sqrt[3]{2^{2} } = \sqrt[3]{2}. 

<span>D.) a^2 is always rational
This one is false. If you square a rational number, you will always end with another rational number.

</span><span>E.) square root of a is never rational
</span>This one is false. The square root of perfect squares are always rational numbers: \sqrt{64} =8, \sqrt{16} =4,...

F.) square root of b is never rational
This one is true. Since the square root of any non-perfect square number is irrational, and all the irrational numbers are non-perfect squares, the square root of an irrational number is always irrational.

We can conclude that given that<span> a is a rational number and b be an irrational number, A, C, D, and F are true statements.</span>
4 0
3 years ago
X^(2)-4x-17=0<br> Please show work step by step
Dimas [21]

Step-by-step explanation:

It seems here that they are asking us to solve for x

to do this we first need to factor

Since we can't factor this using the normal method we can instead do this

x^2 -4x-17=0

add 4 to both sides as it is a perfect square

x^2 - 4x + 4  = 17 +4

(x-2)^2 = sqrt 21

x-2 = ±  4.58

x -2 = 4.58    x-2 = -4.58

x= 6.58          x=-2.58

Or just say x=2+√21 or x=2−√21

7 0
3 years ago
Please help test due today! Will mark brainliest!
Flauer [41]

Answer:

Step-by-step explanation:

JT = 19. 3(4) + 7

37 = CJ + JT

37 = 3x + 6 + 3x + 7

37 = 6x + 13

24 = 6x

X = 4

6 0
2 years ago
Read 2 more answers
Since the slope of a vertical line is undefined, is it possible ofr vertical lines to be parallel?
ikadub [295]

Yes, because if you have x=5 and x=10 they are parallel lines to each other.

6 0
3 years ago
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