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3 years ago

Solve the equation 8-6z=26

Mathematics

2 answers:

Ne4ueva [31]3 years ago

7 0

8-6z=26

8-8-6z=26-8

-6z=18

divide by -6 for -6z and 18

-6z/-6=18/-6

z=-3

Check answer by using substitution method

8-6(-3)=26

8+18= 26

26=26

Answer is z=-3

Katena32 [7]3 years ago

3 0

Answer:

answer - 3

Step-by-step explanation:

8 - 6z = 26 Subtract 8 from both sides.

8-8 - 6z = 26 - 8

- 6z = 18 Divide by - 6

-6z/-6 = 18/-6 Do the division. Note: you must leave the letter with 1 in front of it.

z = - 3

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If l is Parallel to m, find the value of y

BARSIC [14]

Step-by-step explanation:

1st

8x-59 + 2x-11 = 180

10x -70 = 180

10x = 180 + 70

10x = 250

x = 25

2nd

8x - 59 = 15y + 6

8(25) -59 = 15y + 6

200 -59 = 15y + 6

141 = 15y + 6

15y + 6 = 141

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5 0

3 years ago

Read 2 more answers

For the given expression, which whole number (w) will make the expression true? 5/6

Sonja [21]

Answer:

D. 7

Step-by-step explanation:

The question is incomplete. Here is a possible complete question

For the given expression, which whole number (w) will make the expression true? 5/6 < w/6

A. 3

B. 4

C. 5

D. 7

Given the inequality expression:

5/6 < w/6

Cross multiply

5×6 < 6×w

30<6w

Divide both sides by 6

30/6 = 6w/6

5<w

Reciprocate both sides(this will change the sense of the inequality)

1/5>1/w

Cross multiply

w > 5×1

w>5

This shows that the value of w is a value greater than 5 but not 5. According to the option, the only value greater than 5 is 7. Hence the whole number (w) that will make the expression true is 7

7 0

3 years ago

NEED HELP ASAP Given G (-6,5) and H (2, -7), what is the length of GH

lesya692 [45]

$\bold{\huge{\green{\underline{ Solution }}}}$

$\bold{\underline{ Given}}$

We have given that the coordinates of the end point G and H are ( -6,5) and ( 2, -7 )

$\bold{\underline{To \: Find :- }}$

We have to find the length of GH

$\bold{\underline{Let's \: Begin :- }}$

The coordinates of G = ( -6 , 5 )

The coordinates of H = ( 2 , - 7 )

According to the distance formula, we get :- 

$\purple{\bigstar}\boxed{\sf{Distance\:\:GH=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2\;}}}$

Here, x1 = -6 , x2 = 2 and y1 = 5 , y2 = -7

Subsitute the required values in the above formula 

$\sf{ Distance \:GH = √( -6 - 2)² + ( 5 -(-7))²}$

$\sf{Distance\:GH= √(-8)^2+(5 + 7)^2}$

$\sf{Distance\:GH=√(-8)^2+(12)^2}$

$\sf{ Distance \:GH =√64 + 144 }$

$\sf{ Distance \:GH =√ 208}$

$\sf{ Distance\: GH = √ 2 × 2 × 2 × 2 × 13}$

$\sf{ Distance \:GH = 4√13}$

$\sf{\red{ Hence\: the \: length\:of \: GH \: is \: 4√13 \: units}}$

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2 years ago

I need a little help with this problem: 5k + 1 = 4k - 1

Varvara68 [4.7K]

5k-4k=-1+-1
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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B400%20%5Ctimes%20400%20-%2024%20%5Ctimes%20400%20-%20360%20%5Ctimes%20400%20-%202

max2010maxim [7]

Answer:

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3 years ago