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3 years ago

A trapezoid has an area of 13.5 square inches. If the bases are 3 inches and 6 inches, what is the height of the trapezoid?

Mathematics

2 answers:

IRISSAK [1]3 years ago

3 0

Its three because three divided by two times three plus equal 13.5

lana [24]3 years ago

3 0

Answer:

h = 3 inches

Step-by-step explanation:

A = (B + b)/2×h

13.5 = (6 + 3)/2×h

27 = 9h

h = 27 : 9

h = 3 inches

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Find the magnitude and direction in degrees of the vector v=6i+2 seq31

masha68 [24]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the vector

v = 6i + 2√3j

The Magnitude of a vector:

$\mathrm{Computing\:the\:Euclidean\:Length\:of\:a\:vector}:\quad \left|\left(x_1\:,\:\:\ldots \:,\:\:x_n\right)\right|=\sqrt{\sum _{i=1}^n\left|x_i\right|^2}$

$=\sqrt{6^2+\left(2\sqrt{3}\right)^2}$

$=\sqrt{36+12}$

$=\sqrt{48}$

$\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

$=\sqrt{3}\sqrt{2^4}$

$=4\sqrt{3}$

The Direction of a vector:

tan Ф = y/x

y=2√3

x = 6

tan Ф = y/x

= 2√3 / 6

= √3 / 3

$\theta \:=tan\:^{-1}\left(\frac{\sqrt{3}}{3}\right)$

$\:\theta \:=\frac{\pi \:}{6}=30^{\circ \:}$

6 0

3 years ago

The coordinate of centroid of a triangle whose vertices are (1,3,-2), (4,5,0), (6,3,9) is = ……………….

Dominik [7]

Answer:

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

Step-by-step explanation:

Given

$(x_1,y_1,z_1) = (1,3,-2)$

$(x_2,y_2,z_2) = (4,5,0)$

$(x_3,y_3,z_3) = (6,3,9)$

Required

Determine the coordinates of the centroid

Represent the coordinates with C.

C is calculated as follows:

$C = (\frac{1}{3}(x_1+x_2+x_3),\frac{1}{3}(y_1+y_2+y_3),\frac{1}{3}(z_1+z_2+z_3}))$

Substitute values of x and y in the given equation

$C = (\frac{1}{3}(1+4+6),\frac{1}{3}(3+5+3),\frac{1}{3}(-2+0+9}))$

$C = (\frac{1}{3}(11),\frac{1}{3}(11),\frac{1}{3}(7}))$

$C = (\frac{11}{3},\frac{11}{3},\frac{7}{3})$

The above is the coordinate of the centroid

8 0

3 years ago

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Answer:

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Step-by-step explanation:

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Answer:

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