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Dmitriy789 [7]
3 years ago
15

A trapezoid has an area of 13.5 square inches. If the bases are 3 inches and 6 inches, what is the height of the trapezoid?

Mathematics
2 answers:
IRISSAK [1]3 years ago
3 0
Its three because three divided by two times three plus equal 13.5
lana [24]3 years ago
3 0

<em>Answer:</em>

<em>h = 3 inches </em>

<em>Step-by-step explanation:</em>

<em>A = (B + b)/2×h</em>

<em>13.5 = (6 + 3)/2×h</em>

<em>27 = 9h</em>

<em>h = 27 : 9</em>

<em>h = 3 inches </em>

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Percentage increase= $768÷32000=0.024

=0.024×100=2.4%

4 0
2 years ago
A bowl contains 7 pennies, 9 nickels, and 4 dimes. Elyse removes one coin at random from the bowl and does not replace it. She t
Vlad [161]

Answer:

The probability is 3/95

Step-by-step explanation:

Okay this is a probability without replacement question.

Firstly we calculate the total number of coins = 7 + 9 + 4 = 20 coins

The probability that the first coin will be a dimes = number of dimes/total number of coins = 4/20 = 1/5

Now she removes a coin without replacement, if it was a dime, total number of coins becomes 19 and the total number of dimes becomes 3; Thus the probability of the second coins being a dimes = 3/19

Thus, the probability of both coins being dimes = probability of first coin being dimes * probability of second coins being dimes

= 1/5 * 3/19 = 3/95

6 0
3 years ago
Find the exact value of cos 157.5°.
Nonamiya [84]
Cos 157.5º=-cos (180º-157.5º)=-cos 22.5=-cos(45/2)

cos Ф/2=⁺₋√((1+cosФ)/2).

In this case 157.5º is in the second quadrant, therefore we use the following equation:
cos Ф/2=-√((1+cosФ)/2).          (we will have a negative number)

cos 157.5º=-cos (45/2)=-√((1+cos 45º)/2)
=-√((1+√2/2)/2)
=-√((2+√2)/4)
=-√(2+√2) / 2   (≈-0.92387...)

Answer: cos 157.5º= -√(2+√2) / 2

3 0
3 years ago
Match the number with its opposite.
jenyasd209 [6]
A. -1.3
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4 0
3 years ago
Read 2 more answers
Using the sine rule, calculate the length y. Give your answer to 2 s.f.​
Tpy6a [65]

Answer:

y = 9.84 mm

Step-by-step explanation:

<h2>Sine rule:</h2>

Law of sine:

   \sf \boxed{\bf \dfrac{a}{Sin \ A}=\dfrac{b}{Sin \ B}= \dfrac{c}{Sin \ C}}

    a = y

    A = 31°

   b  = 17 mm

    B = 117°

\sf \dfrac{y}{Sin \ 31^\circ}=\dfrac{17}{Sin \ 117^\circ}\\\\

          \sf y = \dfrac{17}{Sin \ 117^\circ}*Sin \ 31^\circ\\\\  y = \dfrac{17}{0.89}*0.515\\\\y = 9.84 \ mm

8 0
2 years ago
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