1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,
6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*
=
(
)
Answer:
Step-by-step explanation:
well, in gonna go under the assumption that by scaled, you mean the length, height, and width have all be increased by a factor of five. the means the volume of my new object could be described as:
V = 5l × 5w × 5h
this can be rewritten as...
V = 125lwh
I know that lwh= original volume, which equals 64. SOO volume can now be rewritten as....
V = 64 (125) = 8000 m^3
if you scaled only length width or height by 5, you would only multiply those parts by 5. let me know of that makes sensr!
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