The approximations of the mean and the standard deviation are 233.3 and 229.82, respectively
<h3>How to determine the mean?</h3>
The table of values is given as:
Savings Lower Limit Upper Limit Frequency
0-199 0 199 345
200-399 200 399 97
400-599 400 599 52
600-799 600 799 21
800-999 800 999 9
1000-1199 1000 1199 8
1200-1399 1200 1399 3
Rewrite the table to include the class midpoint and the frequency
x f
99.5 345
299.5 97
499.5 52
699.5 21
899.5 9
1099.5 8
1299.5 3
The mean is calculated as:
So, we have:
Evaluate
Approximate
Hence, the approximation of the mean is 233.3
<h3>How to determine the standard deviation?</h3>
The standard deviation is calculated as:
So, we have:
Evaluate
Hence, the approximation of the standard deviation is 229.82
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Answer:
1 4/5
Step-by-step explanation:
When you divide 9 into groups of 5, you have one whole group and 4/5 of a second group. Diagram is attached below.
The answer is 10 because the student student did not follow order of op. This means that the student added 25 and 5 together then dived that. However he should have divided 25 by 5 first and then added 5
For every liter of gas there is 1,000 milliliters. If you multiply 50 liters by 1,000 milliliters you will get 50,000mls.