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Ray Of Light [21]
2 years ago
11

Which is an equivalent fraction for

Mathematics
1 answer:
Andru [333]2 years ago
7 0

Answer:

I believe the answer is C

Step-by-step explanation:

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What is the value of x in the following equation 1/5x=5^8 <br> A)-8 B) 8 C)40 D)-40
Monica [59]
The correct question is
What is the value of x in the following equation (1/5)^x=5^8 

Applying logarithms both members
log(1/5)^x=log(5^8) 
x*log(1/5)=8*log(5)
x=8*log(5)/log(1/5)

we know that
log (1/5)----> log (1)-log (5)----> 0-log (5)-----> -log (5)
so
x=8*log(5)/-log (5)------> x=-8

the answer is
-8

7 0
3 years ago
What is the answer to -x/3_&gt;5
den301095 [7]

Answer: this is the answer

( {x}^{3} ) {}^{ - 5}  =  {x}^{ - 15}

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
8 ^ x * 16 ^ x - 1 equals 1​
Lana71 [14]

Answer:

{8}^{x}  \times  {16}^{x }  - 1 = 1 \\  {2}^{3x}  \times  {2}^{4x}  = 1 + 1 \\  {2}^{7x}  =  {2}^{1}  \\ 7x = 1 \\ x =  \frac{1}{7}

7 0
3 years ago
How do I solve this equation: -5/6b + 3/4 = 1/2b - 2/3 ?
Gre4nikov [31]
First get like things on the same side:
-5/6b - 1/2b= -2/3 - 3/4

Then find equivalent fractions to make the equation easier to solve.
-5/6b - 3/6b= -8/12 - 9/12

Then just add things together and solve.
-8/6b= -17/12
-8b= 6(-17/12)
-8b= -17/2
b= (-17/2)/-8
b= 17/16

You can then plug the answer back into the original question to make sure it is the correct answer.
3 0
3 years ago
Let F be a field, and suppose a EF, a *0. Prove that a has a unique multiplicative inverse.
bezimeni [28]

Answer with Step-by-step explanation:

Let F be a field .Suppose a\in F and a\neq 0

We have to prove that a has unique multiplicative inverse.

Suppose a has two inverses b and c

Then, ac=1,ab=1 where 1 =Multiplicative identity

ac=ab

c=b (cancel a on both sides)

Hence, a has unique multiplicative inverse.

6 0
3 years ago
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