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3 years ago

7=5y-13-y

Mathematics

1 answer:

liberstina [14]3 years ago

8 0

Step-by-step explanation:

7=4y-13

7+13=4y

20/4=y

5=y

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Segments in Circles TW=3, CW=x, TU=x+7, VW=6. Find the value of x.

Kryger [21]

Answer:

x=2

Step-by-step explanation:

The diagram is attached below

TW=3
CW=x
TU=x+7
VW=6

TU=TW+WU

x+7=3+WU

WU=x+7-3

WU=x+4

To determine the value of x, we apply the theorem of intersecting chords.

TW X WU = CW X WV

$x(x+4)=6 \times x\\x^2+4x=6x\\x^2=6x-4x\\x^2=2x\\$Divide both sides by x\\x=2$

4 0

3 years ago

2. Solve the equation using the quadratic formula. -4x2 + 40x + 16 = 0 Page 1 of 2

kumpel [21]

The solution to given quadratic equation is x = -0.3851 or x = 10.3851

Solution:

Given equation is:

$-4x^2 + 40x + 16 = 0$

To find: solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16$

Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,

$\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}$

Thus the solution to given quadratic equation is x = - 0.3851 or x = 10.3851

8 0

3 years ago

How do you solve 2 (5-6) < 8f - 130

irga5000 [103]

2(5-6)<8f-130
(2x5)-(2x6)<8f-130
10-12<8f-130
-2<8f-130
-2+130<8f-130+130
128<8f
128/8<8f/8
16<f
f>16

3 0

3 years ago

What is the zero of g(X) = -X - 7

gogolik [260]

(-7,0) (0,-7) should be the zeros

3 0

3 years ago

How to solve this question

Katarina [22]

Direct variation can be written as a proportion. Therefore, we can write:

$\frac{8}{4}= \frac{y}{5}$
Cross multiply to get:
4y=40
Divide by 4 on both sides to get that y=10.

:)

3 0

3 years ago