Find the value of θ,
θ = arccos -8/9 = 152.734 deg
You can substitute this value for the requirement.
tan 152.734 = -0.51539
sin 152.734 = 0.45812
First, find the area of the larger sector (the 360-130=230 degree sector), then add the area of the triangle.
area of the larger sector:(230/360)π*11.1²≈247.17
area of the triangle when two sides and the angle between the two sides are given: (absinФ)/2. In this case, a=11.1, b=11.1, Ф=130
(11.1*11.1*sin130)/2≈47.19
the total area is 247.17+47.19≈294.4
Please use your calculator to double check my numbers.
Look for patterns
1 to 3 is plus 2
3 to 6 is plus 3
6 to 10 is plus 4
Answer:
3 2/3 inches (the last one)
Write the division as a fraction
2/3x - 8 = 9
Multiply both sides of the equation by 3
2x-24=27
Move the constant to the right and change the sign
2x=27+24
Add the numbers
2x=51
Divide both sides by 2
2x/2=51/2
X= 25.5
